Answer:
Assessment zone
Explanation:
It is the assessment zone in various security zones where active and passive security measures are employed to identify, detect, classify and analyze possible threats inside the assessment zones.
Answer:
180 m
Explanation:
Given:
Uniform speed of the car, U = 30 m/s
Uniform acceleration of the motorcycle = 10 m/s²
For the motorcycle to catch up with the car, the distance traveled must be the same.
For the car;
Distance = Speed × Time
⇒ d = u × t
d = 30 × t
d = 30t ......(1)
For the motorcycle;
The stationary police motorcycle has initial speed, u = 0
From equation of motion;

but u = 0

.....(2)
Equating equation (1) and (2)
30t = 5t²

t = 6 seconds
Substituting t = 6 s into equation (2)
d = 5(6)²
d = 5 × 36
d = 180 m
The motorcycle must travel 180 m before it catches up to the car
Answer:
(a): The car's relative position to the base of the cliff is x= 32.52m.
(b): The lenght of the car in the ir is tfall= 1.78 sec.
Explanation:
Vo= 0
V= ?
d= 50m
h= 30m
a= 4 m/s²
t= √(2*d/a)
t= 5 sec
V= a*t
V= 20 m/s
Vx= V * cos(24º)
Vx= 18.27 m/s
Vy= V* sin(24º)
Vy= 8.13 m/s
h= Vy*t + g*t²/2
clearing t:
tfall= 1.78 sec (b)
x= Vx * tfall
x= 32.52 m (a)