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Alisiya [41]
1 year ago
10

3. NASA launched the Voyager spacecraft with a mission to observe Jupiter and Saturn. In 1990,

Mathematics
1 answer:
makkiz [27]1 year ago
5 0

The linear function that calculates the expected distance from the sun of the Voyager-2 spacecraft in x years after 1990 is given by:

y = 3.3x + 30.6.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, we have that the distance increases 33 AU each 10 years, hence the slope is given by:

m = 33/10 = 3.3.

Hence:

y = 3.3x + b.

When x = 28, y = 123, hence we use it to find b as follows:

123 = 3.3(28) + b

b = 30.6.

Hence equation to calculate the expected distance from the sun of the Voyager-2 spacecraft in x years after 1990 is given by:

y = 3.3x + 30.6.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

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Answer:

5x = 5^{(a+1)}

Step-by-step explanation:

Here is a problem with the concept of properties of the exponent.

We are given x = 5^{a} and we have to find the value of 5x.

Now, 5x = 5 \times 5^{a} {Since we are given that x = 5^{a}}

⇒ 5x = 5^{1} \times 5^{a} {Since we can write x = x^{1}}

⇒ 5x = 5^{(a+1)} {Since we know the formula of exponent as x^{m} \times x^{n} = x^{(m + n)}}

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Y =  2.
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What is the simplified form of the expression? k3 [k^7/3] -5
iragen [17]
Simplify the following:
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Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
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Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
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The population of a town is increasing at a rate of 6.2% per year. The city council believes they will have to add another eleme
kow [346]

Answer:

The correct solution is "4.6".

Step-by-step explanation:

Given:

Interest rate,

r = 6.2%

or,

 = 0.062

Amount,

A = 100000

Principle,

P = 76000

As we know,

⇒ A=P(1+\frac{r}{100} )^n

On substituting the values, we get

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⇒ (1+0.062)^n=\frac{100}{76}

On taking log both sides, we get

⇒ n \ log_e(1.062)=log_e(\frac{100}{76} )

⇒                   n=\frac{ln(\frac{100}{76} )}{ln(1.062)}

By putting the values of log, we get

⇒                      =4.5622

or,

⇒                      =4.6

5 0
2 years ago
What is the value of the product (3-2)(3 + 2)?
Veseljchak [2.6K]

Answer:

5

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