Answer:
i. Point A
ii. None
iii. All points
iv. F
v. None
vi. All
vii. None
Explanation:
i. Not quite sure if I'm interpreting the diagram right, but from the second the ball is released, it will start accelerating. Point A is where the velocity will be closest to 0 but not necessarily 0 as it will have started accelerating downwards.
ii. Assuming standard directions for vectors, the velocity is positive at none of the points as the ball is travelling in a downwards direction.
iii. Since the ball is always travelling downwards, its direction and therefore velocity is a negative number at all points in this diagram.
iv. The ball is accelerating as it falls so the further or the longer it falls, the faster its velocity, therefore in this diagram, it is fastest at point F.
v and vi. Assuming same direction principles as ii and iii (as acceleration and velocity are both vectors), acceleration is always downwards, therefore it is positive at no points, and negative at all of them.
vii. Acceleration due to gravity is always constant, so unless the ball is not moving (being held by the boy), acceleration is not 0 at any of the points.
Hope this helped!
