Question

It takes 18 J of energy to move a 0.30 mC charge from one plate of a 15 mF capacitor to the other. How much charge is on each plate

Answer 1

The amount of charge on each plate is equal to 0.9 Coulombs.

Given the following data:

• Work done = 18 J

• Charge = 0.30 mC

• Capacitance = 15 mF

To calculate the amount of charge on each plate:

The formula for work done.

Mathematically, work done in moving a charge is given by this formula:

$W=qV$

Note: The work done by an external force equals the change in potential energy for the charges that were moved.

$W= \Delta P.E = qV$

But, $V=\frac{Q}{C}$

Now, the work done becomes:

$W=q\frac{Q}{C}$

Making q the subject of formula, we have:

$q=\frac{WC}{Q} \\\\q=\frac{18 \times 15 \times 10^{-6}}{0.3 \times 10^{-3}}$

Charge, q = 0.9 Coulombs.

Read more on charge here: brainly.com/question/14327016