Question

Two particles are 15 meters apart. Particle A has a charge of 6.0 • 10-4 C, and particle B has a charge of 5.0 • 10-4 C. The resulting Coulomb force is 12 N. At the same distance, what combination of charges would yield the same Coulomb force?

Answer 1

Answer:

The combinations are

1. $2\times 10^{-4}$ C , $15\times 10^{-4}$

2. $3\times 10^{-4}$ C , $10\times 10^{-4}$

Explanation:

The force between two charges q and Q is given by Coulomb's law.

The coulomb force is given by

$F = \frac{1}{4\prod \varepsilon _{0}}\times \frac{Q\times q}{r^{2}}$

Where, r be the distance between two charges

According to the question,

r = 15 cm, Q = $6\times 10^{-4}$ C, q = $5\times 10^{-4}$ C , F = 12 N

Force remains same, distance remains same

so the product of Q and q be same

The product of Q and q is $30\times 10^{-8}$

So other combination of charges are

1. $2\times 10^{-4}$ C , $15\times 10^{-4}$

2. $3\times 10^{-4}$ C , $10\times 10^{-4}$