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Irina-Kira [14]
3 years ago
11

You compress a spring by a certain distance. then you decide to compress it further so that its elastic potential energy increas

es by another 50%. what was the percent increase in the spring's compression distance?
Physics
1 answer:
Likurg_2 [28]3 years ago
5 0
Elastic potential energy = 1/2 k * change of x^2
k- coefficient
x - change in length.
to increase energy 1.5 times you have to change x (compress) into \sqrt{1.5}  times (it's abot 1.22 or 22%)
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a ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. what is the final velocity of the
Y_Kistochka [10]

Answer:

3.2(6.0) = 19.2 m/s

Explanation:

6 0
3 years ago
Doubling the frequency of a wave source doubles the speed of the wave assuing that wavelength remains the same? True or false? W
SVETLANKA909090 [29]

Answer:true,because velocity is directly proportional to speed or velocity

Explanation:

Velocity = frequency x wavelength

The velocity or speed varies directly with the frequency, so as the frequency is increased, the velocity or speed is also increased

8 0
2 years ago
The weight of an astronaut plus his space suit on the Moon is only 250 N. (a) How much does the suited astronaut weigh on Earth?
Evgesh-ka [11]

Answer:

a)1500N

b)153.06kg

Explanation:

F = ma

g(moon) = is the acceleration due to gravity on the moon

g(earth) is the acceleration due to gravity on the earth

g(moon) = 1/6g(earth)

g(earth) =6g(moon)

F(gearth) = mg(earth)

               = m 6g(moon)

               = 6 × 250

               = 1500N

b) F(gearth) = mg(earth)

m = F /g

 = 1500/9.8

 = 153.06kg

3 0
3 years ago
Read 2 more answers
At the surface, atmospheric pressure is 1.013 × 10^5 Pa. People can normally snorkel down to a depth of roughly one meter. What
natulia [17]

Answer:

1.01 × 10⁵ Pa  

Explanation:

At the surface, atmospheric pressure is 1.013 × 10⁵ Pa.

We need to find the total pressure on the air in the lungs of a person to a depth of 1 meter.

Pressure at a depth is given by :

P=\rho gh

Where

\rho is the density of air, \rho=1.225\ kg/m^3

So,

P=1.225\times 9.8\times 1\\\\=12\ Pa

Total pressure, P = Atmospheric pressure + 12 Pa

= 1.013 × 10⁵ Pa + 12 Pa

= 1.01 × 10⁵ Pa

Hence, the total pressure is 1.01 × 10⁵ Pa.

5 0
2 years ago
In order to open the clam it catches, a seagull will drop the clam repeatedly onto a hard surface from high in the air until the
Vedmedyk [2.9K]

Answer:

2.2 s

Explanation:

Hi!

Let's consider the origin of the coordinate system at the ground, and consider that the clam starts with zero velocity, the equation of motion of the clam is given by

x(t) = 23.1 m - \frac{1}{2}(9.8 m/s^2) t^2

We are looking for a time t for which x(t) = 0

0 = 23.1 m - (4.9 m/s^2) t^2

Solving for t:

t = \sqrt{\frac{23.1}{4.9}} s = 2.17124 s

Rounding at the first decimal:

t = 2.2 s

4 0
2 years ago
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