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Irina-Kira [14]
3 years ago
11

You compress a spring by a certain distance. then you decide to compress it further so that its elastic potential energy increas

es by another 50%. what was the percent increase in the spring's compression distance?
Physics
1 answer:
Likurg_2 [28]3 years ago
5 0
Elastic potential energy = 1/2 k * change of x^2
k- coefficient
x - change in length.
to increase energy 1.5 times you have to change x (compress) into \sqrt{1.5}  times (it's abot 1.22 or 22%)
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The ratio of the inductive reactance to the
BARSIC [14]

Answer:

<em>The non resonance frequency of the generator is = 1201.79 Hz</em>

Explanation:

At resonance,

f₀ = 1/2π√LC..................... Equation 1

Where f₀ = resonance frequency, L = inductance, C = capacitance

making LC the subject of the equation

LC = 1/4πf₀²..................... Equation 2

<em>Given: </em>f₀ = 225 Hz, and π = 3.143

<em>Substituting these values into equation 2,</em>

LC = 1/(4×3.143²×225²)

LC = 1/2000385.9

LC = 5×10⁻⁷

If the ratio of capacitive reactance to inductive reactance = 5.36

1/2πfC/2πfL = 5.36

1/4π²f²LC = 5.36

Where f = frequency of the non resonant

making f the subject of the equation

f = 5.36/2π√LC ............. Equation 3

Substituting the value of LC = 5×10⁻⁷ into equation 3

f = 5.36/2×3.143√(5×10⁻⁷)

f = 5.36/(6.286×0.00071)

f = 5.36/0.00446

<em>f = 1201.79 Hz</em>

<em>Thus the non resonant frequency of the generator is = 1201.79 Hz</em>

6 0
3 years ago
Two balls are kicked with the same initial speeds. Ball A was kicked at the angle 20° above horizontal and ball B was kicked at
GREYUIT [131]

Answer:

Ball A

Explanation:

Let the initial speed of the balls be u .

Angle of projection for ball A = 20°

Angle of projection for ball B = 75°

As we know that at highest point, the ball has only horizontal speed which always remains constant throughout the motion because the acceleration in horizontal direction is zero.

Speed of ball A at highest point = u Cos 20° = 0.94 u

Speed of ball B at highest point = u Cos 75° = 0.26 u

So, the ball A has bigger speed than B.

5 0
3 years ago
What is mechanics? Give name of its two sub branch?
kap26 [50]

Answer:

Mechanics is the branch of physics which deals with the motion of objects its causes and effects.

Sub branches

kinematics(deals with motion of objects without studying the cause of its motion)

dynamic(deals with the motion and cause of motion of objects)

Explanation:

3 0
3 years ago
A speeding car is pulling away from a police car. The police car is moving at 30 m/s. The radar gun in the police car emits an e
Gekata [30.6K]

Answer:

65.625 m/s

Explanation:

F=20\times 10^9 Hz

\Delta F=F_r-F_t=4750 Hz

c = Speed of light = 3×10⁸ m/s

Relative speed

v=\frac{\Delta F}{2F}\times c\\\Rightarrow v=\frac{4750}{2\times 20\times 10^9}\times 3\times 10^8\\\Rightarrow v=35.625\ m/s

Relative speed = 35.625 m/s

Velocity of speeder = Velocity of police car + Relative speed

⇒Velocity of speeder = 30 + 35.625 = 65.625 m/s

∴ Velocity of speeder is 65.625 m/s

6 0
3 years ago
An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
Papessa [141]

Answer:

\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

Explanation:

From the given information, the LED is operating with a given wavelength of 850 nm or 0.85 μm.

Hence, the material dispersion is \dfrac {d \tau _{mat}}{d \lambda } \simeq (80 \ ps / (nm.km) \ )

Now, using the pulse spread formula:

\dfrac{\sigma_{mat}}{L} = \dfrac{d \tau _{mat} }{d \lambda} \sigma \lambda

\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ )  \times (45 \ nm)

Thus, the pulse spreading as a result of  material dispersion is:\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

3 0
3 years ago
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