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hammer [34]
1 year ago
10

1) What is the area of the rectangle? 4 yd 7yd

Mathematics
2 answers:
Brums [2.3K]1 year ago
8 0
28 hope this helps :)
guapka [62]1 year ago
6 0

Answer:

Area = 28

Step-by-step explanation:

Area = L x W

L = 7

W = 4

Area=7 x 4

Area = 28

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Solve: log(2)(3x + 8) = 5 Which is an equivalent equation?
Rzqust [24]

You can just simplify to make an equivalent equation:

(2)(3x + 8) = 5 ⇒ 6x + 16 = 5


Answer:

\boxed{\bf~6x + 16 = 5}


Hope it helped,


BioTeacher101


<em>(If you have any questions feel free to ask them in the comments)</em>


8 0
3 years ago
Read 2 more answers
Two basketballs are thrown along different paths. Determine if the basketballs’ paths are parallel to each
Paul [167]

Answer:

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

Step-by-step explanation:

Remember that:

  • Two lines are parallel if their slopes are equivalent.
  • Two lines are perpendicular if their slopes are negative reciprocals of each other.
  • And two lines are neither if neither of the two cases above apply.

So, let's find the slope of each equation.

The first basketball is modeled by:

\displaystyle 3x+4y=12

We can convert this into slope-intercept form. Subtract 3<em>x</em> from both sides:

4y=-3x+12

And divide both sides by four:

\displaystyle y=-\frac{3}{4}x+3

So, the slope of the first basketball is -3/4.

The second basketball is modeled by:

-6x-8y=24

Again, let's convert this into slope-intercept form. Add 6<em>x</em> to both sides:

-8y=6x+24

And divide both sides by negative eight:

\displaystyle y=-\frac{3}{4}x-3

So, the slope of the second basketball is also -3/4.

Since the slopes of the two equations are equivalent, the basketballs' paths are parallel.

3 0
2 years ago
Somebody please help me with this
kap26 [50]

Answer:

D. $7/hour

Step-by-step explanation:

128-86=42

42/6=7

6 0
2 years ago
Read 2 more answers
Which of the following expression is equal to x^2+25?
nignag [31]
A: (x + 5i)^2
= (x + 5i)(x + 5i)
= (x)(x) + (x)(5i) + (5i)(x) + (5i)(5i)
= x^2 + 5ix + 5ix + 25i^2
= 25i^2 + 10ix + x^2


B: (x - 5i)^2
= (x  +   - 5i)(x +  - 5i)
= (x)(x) + (x)(- 5i) + (- 5i)(x) + (- 5i)(- 5i)
= x^2 - 5ix - 5ix + 25i^2
= 25i^2 - 10ix + x^2


C: (x - 5i)(x + 5i)
= (x +  - 5i)(x + 5i)
= (x)(x) + (x)(5i) + (- 5i)(x) + (- 5i)(5i)
= x^2 + 5ix - 5ix - 25i^2
= 25i^2 + x^2


D: (x + 10i)(x  - 15i)
= (x + 10i)(x +  - 15i)
= (x)(x) + (x)(- 15i) + (10i)(x) + (10i)(- 15i)
= x^2 - 15ix + 10ix - 150i^2
=  - 150i^2 + 5ix + x^2



Hope that helps!!!

6 0
3 years ago
Read 2 more answers
Solve the following for y: −6x + 2y = 8
Masteriza [31]
-6x + 2y = 8
isolate the y
first add 6x to both sides
2y = 6x + 8 
then divide everything by 2 to isolate the y
y = 3x + 4

Hope this helps
6 0
2 years ago
Read 2 more answers
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