The similarity ratio of ΔABC to ΔDEF = 2 : 1.
Solution:
The image attached below.
Given ΔABC to ΔDEF are similar.
To find the ratio of similarity triangle ABC and triangle DEF.
In ΔABC: AC = 4 and CB = 5
In ΔDEF: DF = 2, EF = ?
Let us first find the length of EF.
We know that, If two triangles are similar, then the corresponding sides are proportional.
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⇒ 
⇒ 
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Ratio of ΔABC to ΔDEF = 
Similarly, ratio of ΔABC to ΔDEF = 
Hence, the similarity ratio of ΔABC to ΔDEF = 2 : 1.
Lines <em>a</em> and <em>b</em> are parallel, so lines <em>p</em>, <em>q</em>, and <em>t</em> are considered to be transversals. To solve this, you make use of the fact that alternate interior angles are equal, as are alternate exterior angles, as are corresponding angles. Of course any linear pair of angles is supplementary.
∠1 = 90° — corresponding angle to the right angle above it
∠2 = 68° — the sum of 22° and angles 1 and 2 is 180°
∠3 = 112° — supplementary to angle 2 (and the sum of 22° and 90°, opposite interior angles of the triangle)
∠4 = 112° — equal to angle 3
∠5 = 68° — equal to angle 2; supplementary to angle 4
∠6 = 56° — base angle of isosceles triangle with 68° at the apex; the complement of half that apex angle
∠7 = 124° — supplementary to the other base angle, which is equal to angle 6; also the sum of angles 5 and 6
∠8 = 124° — alternate interior angle with angle 7, hence its equal.
Answer: 4/6+4/6 is 8/12 and bigger than 3/5
Step-by-step explanation:
1) 2x + 3y = 12 -> 3y = -2x +12 -> y = -2/3x + 4
2) 4y - 7x = 16 -> 4y = 7x + 16 -> y = 7/4x + 4