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Sunny_sXe [5.5K]
1 year ago
9

PLEASE HELP!

Mathematics
1 answer:
balandron [24]1 year ago
3 0

The inequality equation represented by the parabola graph is;

y < (x - 2)(x - 8)

<h3>How to Interpret a Quadratic Graph?</h3>

We are told that the zeros of a parabola are 2 and 8. This means that the roots of the quadratic equation represented by the graph are 2 and 8. Thus, the factors of this quadratic graph can be written as;

(x - 2) and (x - 8)

Now, one rule about graphing inequalities is that If the inequality symbol is ≤ or ≥ , then the region includes the parabola, so it should be graphed with a solid line.

Otherwise, if the inequality symbol is < or > , the parabola should be drawn with a dotted line to indicate that the region does not include its boundary.

Now, since the parabola is drawn with a dashed line, it means that the inequality sign will be  < or > .

Lastly, since the outside of the parabola is shaded, it means that the inequality will be less than. Thus, our inequality equation is;

y < (x - 2)(x - 8)

Read more about Quadratic Graphs at; brainly.com/question/7784687

#SPJ1

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In this question weight of a flea and an ant is given, but their units are different. So comparing and finding out the weight of flea and ant would be difficult. First thing that needs to be done is to bring the units of both the flea and the ant under same unit.
Weight of flea = 8 decigrams
Weight of ant = 3 milligrams.
Now let us convert the weight of the flea from decigrams to milligrams.
We already know that
1 decigram = 100 milligram
Then
8 decigrams = 100 * 8 milligrams
                     = 800 milligrams
Then
The weight by which the flea is greater than the ant = (800 - 3) milligrams
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So the flea weighs 797 milligrams more than the ant.

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3 years ago
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7 0
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Complete the table for the radioactive iotope. (Round your anwer to 2 decimal place. Iotope : 239 Pu
Marizza181 [45]

If the radio active isotope has the half life of 24100 years, then the initial quantity is 2.16 grams

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y = Ce^{kt}

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Substitute the values in the equation

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Cancel the C in both side

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Here we have to apply ln to eliminate the e terms

ln (1/2) = 24100k

k = ln(1/2) / 24100

k = -2.87× 10^-5

To find the initial value we have to substitute the value of k and y in the equation

1.2 = Ce^{1000 ×  -2.87× 10^-5}

C = 1.2 / e^(-0.0287)

C = 2.16 gram

Hence, the initial quantity of the radioactive isotope is 2.16 gram

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7 0
1 year ago
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Answer:

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