Explanation :
The balanced chemical reaction is,
The expression for the rates of consumption of the reactants are:
The rate of consumption of 
= ![-\frac{1}{5}\frac{d[Br^-]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D)
The rate of consumption of 
= ![-\frac{d[BrO_3^-]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BBrO_3%5E-%5D%7D%7Bdt%7D)
The rate of consumption of 
= ![\frac{1}{6}\frac{d[H^+]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D)
The expression for the rates of formation of the products are:
The rate of consumption of 
= ![+\frac{1}{3}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The rate of consumption of 
= ![+\frac{1}{3}\frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
The correct answer is c, it’s evaporating there for it’s a chemical change
Answer:
Four electrons are present in the valence shell of Silicon.
Explanation:
Valence shell electrons are those electrons which are present in the outermost shell of an atom. These valence shell electrons are responsible for in the formation of bonds with other atoms.
Silicon having atomic number 14 has fourteen electrons in its neutral state and has the electronic configuration as follow;
1s², 2s², 2p⁶, 3s², 3p²
In given configuration the valence shell (outermost shell) is 3 and the number of electrons present in it are four i.e. 3s² and 3p² (2 + 2 = 4) respectively.
ok, now press calculator. i dont have it now.
The electron configuration
1
s
2
2
s
2
2
p
6
3
s
2
3
p
2
is the element Silicon.
The key to deciphering this is to look at the last bit of information of the electron configuration
3
p
2
.
The '3' informs us that the element is in the 3rd Energy Level or row of the periodic table. The 'p' tells us that the element is found in the p-block which are all of the Groups to the right of the transition metals, columns 13-18. The superscript '2' tells us that the element is found in the 2nd column of the p-block Group 14.
