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Bingel [31]
2 years ago
5

QUESTION 19

Chemistry
1 answer:
spayn [35]2 years ago
8 0

The statement is false. Sara's trouble with listening to the lecture in class because she had just had an argument with her best friend is not an example of physical noise.

A physical noise refers to a situation whereby communication is impeded by sound coming from outside the individual such as music blaring out of a horn speaker.

Another type of noise is psychological noise. This arises when the receiver of a message is distracted by his/her internal thought processes.

Sara is clearly experiencing a psychological and not a physical noise.

Learn more: brainly.com/question/537365

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The product of 2 × 104 cm and 4 × 10–12 cm, expressed in scientific notation is ____.
Hatshy [7]

Answer:

b,,

Explanation:

7 0
3 years ago
A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c
stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568  moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054  moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0
2 years ago
Which landscape is located at 42°N 75° W
vovikov84 [41]
The answer would be <span>Tug Hill Plateau</span>
7 0
3 years ago
Which element is used to reduce metal oxides and make pure metals?
Setler [38]

Can vary. Carbon is used quite commonly, and extracts metal oxides, works with zinc, iron, tin, lead and copper.

5 0
3 years ago
How many molecules are in 3 moles of NaCl?
PtichkaEL [24]

Answer:

Given : No. Of moles = 1.5

To calculate : no. Of molecules =N

We know that moles = N / 6.022 x 10²³

Therefore, 1.5 x 6.022 x 10²³ = N

Hence N = 9.0330x 10²³ molecules

3 0
3 years ago
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