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Mazyrski [523]
2 years ago
8

Both amines and amides are derivatives of ammonia. True False

Chemistry
2 answers:
Alenkinab [10]2 years ago
7 0
<h2>Answer:</h2>

It is true that both amides and amine are the derivatives of ammonia.

<h2>Explanation:</h2>

Amines are the derivatives of ammonia \text{(NH_3)} where nitrogen atom makes bond to 1, 2, or 3 alkyl or aromatic groups of compounds. Amides are the amino group \text{(-NH_2)}, which is derived from ammonia, replaces the hydroxyl group \text{(-OH)} in a carboxylic acid.

The simplest amides are the proper derivation of ammonia whereas the higher degree amides are the derivation of secondary amine.  

Ronch [10]2 years ago
3 0

Answer:

true

Explanation:

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3 years ago
Help this is an earthquake thing
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Answer:

im pretty sure its a push or pull thing

Explanation:

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10.0 g of calcium carbonate was heated. The mass of calcium oxide left was 5.6 g. Calculate the mass of
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Answer:

4.4g

Explanation:

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4 0
3 years ago
Read 2 more answers
Design a test to determine whether thorium-234 also emits particles. First, explain how Rutherford’s experiment measured positiv
liubo4ka [24]

The characteristics of the α and β particles allow to find  the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the beta particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

In Rutherford's experiment, the positive particles directed to the gold film were measured on a phosphorescent screen that with each arriving particle a luminous point is seen.

The particles in this experiment are α particles that have two positive charge and two no charged is a helium nucleus.

The test that can be carried out is to place a small ours of Thorium in front of a phosphorescent screen and see if it has flashes, with the amount of them we can determine the amount of particle emitted per unit of time.

Thorium has several isotopes, with different rates and types of emission:

  • ²³²Th emits α particles, it is the most abundant 99.9%
  • ²³⁴Th emits β particles, exists in small traces.

In this case they indicate that the material used is ²³⁴Th, which emits β particles that are electrons, the detection of these particles is more difficult since it has one negative charge, it has much lower mass, but they can travel further than the particles α, therefore, for what type of isotope we have, we can start measuring at a small distance and increase the distance until the reading is constant. At this point all the particles that arrive are β, which correspond to ²³⁴Th.

Neutron detection is much more difficult since these particles have no charge and therefore do not interact with electrons and no flashing on the screen is varied.

In conclusion with the characteristics of the α and β particles we can find the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the β particle emission from ²³⁴Th.
  • The neutrons cannot be detected in this experiment because they have no electrical charge.

Learn more about radioactive emission here: brainly.com/question/15176980

7 0
2 years ago
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Ni (Nickel) is the best conductor, and in fact the only conductor, in that list
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3 years ago
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