Simplify the following:
x^3 - 2 x^3 + x - 3 x - 5 - 4
Grouping like terms, x^3 - 2 x^3 + x - 3 x - 5 - 4 = (-2 x^3 + x^3) + (x - 3 x) + (-5 - 4):
(-2 x^3 + x^3) + (x - 3 x) + (-5 - 4)
x^3 - 2 x^3 = -x^3:
-x^3 + (x - 3 x) + (-5 - 4)
x - 3 x = -2 x:
-x^3 + -2 x + (-5 - 4)
-5 - 4 = -9:
-x^3 - 2 x + -9
Factor -1 out of -x^3 - 2 x - 9:
Answer: -(x^3 + 2 x + 9)
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Yes = (-2x^3 + x - 5)+( x^3 - 3x - 4) = ( x^3 - 3x - 4)+(-2x^3 + x - 5) = True
Proof:
Left side
Simplify the following:
x^3 - 2 x^3 + x - 3 x - 5 - 4
Grouping like terms, x^3 - 2 x^3 + x - 3 x - 5 - 4 = (-2 x^3 + x^3) + (x - 3 x) + (-5 - 4):
(-2 x^3 + x^3) + (x - 3 x) + (-5 - 4)
x^3 - 2 x^3 = -x^3:
-x^3 + (x - 3 x) + (-5 - 4)
x - 3 x = -2 x:
-x^3 + -2 x + (-5 - 4)
-5 - 4 = -9:
-x^3 - 2 x + -9
Factor -1 out of -x^3 - 2 x - 9:
<span>Answer: -(x^3 + 2 x + 9)
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Right Side.
Simplify the following:
x^3 - 2 x^3 + x - 3 x - 5 - 4
Grouping like terms, x^3 - 2 x^3 + x - 3 x - 5 - 4 = (x^3 - 2 x^3) + (-3 x + x) + (-4 - 5):
(x^3 - 2 x^3) + (-3 x + x) + (-4 - 5)
x^3 - 2 x^3 = -x^3:
-x^3 + (-3 x + x) + (-4 - 5)
x - 3 x = -2 x:
-x^3 + -2 x + (-4 - 5)
-4 - 5 = -9:
-x^3 - 2 x + -9
Factor -1 out of -x^3 - 2 x - 9:
Answer: -(x^3 + 2 x + 9)
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Answer:
y=-x+3
Step-by-step explanation:
Three consecutive numbers are x, x+1 and x+2.
Four times the first integer is 4x
The sum of the second and third is (x+1)+(x+2)=2x+3.
So, we have
Subtract 2x from both sides:
Divide both sides by 2:
So, you can't have three consecutive integers such that four times the first is 18 more than the sum of the other two: the three numbers would be 10.5, 11.5, 12.5.
In fact, you have
and
The answer is B it's ordered from least to greatest
The answer is (●’◡’●)ノ BBBB !!!