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AlekseyPX
3 years ago
14

Simplify this expression: 4p + 9 + (–7p) + 2 = ?

Mathematics
2 answers:
belka [17]3 years ago
8 0
Ok, so what you want to do is begin with parentheses, and multipl the positive sign (which is 1, because if there is no number there, it will always be one, whether it is negative or positive) and your equation will now be:

4p + 9 - 7p + 2.
Next, you will want to simplify, or combine like terms. And you know, you now have 4p, -7p, +9, and +2. So, add together the 9 and 2 to get 11, and you subtract 7p from 4p to get -3p. So, your final answer will be C, -3p + 11. 
Alexeev081 [22]3 years ago
7 0
C.

The answer is C :)

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Answer:

Speed of the plane in still air: 779\; {\rm km \cdot h^{-1}}.

Windspeed: 100\; {\rm km \cdot h^{-1}}.

Step-by-step explanation:

Assume that x\; {\rm km \cdot h^{-1}} is the speed of the plane in still air, and that y\; {\rm km \cdot h^{-1}} is the speed of the wind.

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The question states that when going against the wind (v = (x - y)\; {\rm km \cdot h^{-1}},) the plane travels 6111\; {\rm km} in 9\; {\rm h}. Hence, 9\, (x - y) = 6111.

Similarly, since the plane travels 7911\; {\rm km} in 9\; {\rm h} when travelling in the same direction as the wind (v = (x + y)\; {\rm km \cdot h^{-1}},) 9\, (x + y) = 7911.

Add the two equations to eliminate y. Subtract the second equation from the first to eliminate x. Solve this system of equations for x and y: x = 779 and y = 100.

Hence, the speed of this plane in still air would be 779\; {\rm km \cdot h^{-1}}, whereas the speed of the wind would be 100\; {\rm km \cdot h^{-1}}.

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1 year ago
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