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adoni [48]
3 years ago
15

Fred Buys a signed shirt for £25 and sells it for £40. What is the percentage profit? explaination please?

Mathematics
2 answers:
frozen [14]3 years ago
5 0
Profit % =propfit\cost x 100
profit=40-25=15
15\25 x 100=60%
bogdanovich [222]3 years ago
4 0
Percent increase : (new number - original number) / (original number)....x 100

(40 - 25) / 25 = 15/25 reduces to 3/5.....x 100 = 60% profit
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Please Please Please help me with the answer
Tems11 [23]

c = amount of chocolate donuts

m = amount of maple donuts.

so we know the total in all is 41 donuts, thus c + m = 41.

we also know that whatever c is, m is 25 fewer than that, m = c - 25.

\bf \begin{cases} c+m=41\\ \boxed{m}=c-25\\ --------\\ c+\boxed{c-25}=41 \end{cases} \\\\\\ 2c-25=41\implies 2c=66\implies c=\cfrac{66}{2}\implies c=33 \\\\\\ \stackrel{\textit{since c = 33}}{m = c - 25}\implies m=33-25\implies m = 8

6 0
3 years ago
Read 2 more answers
A carpenter is building a rectangular shed with a fixed perimeter of 54 ft. What are the dimensions of the largest shed that can
lutik1710 [3]

Answer:

the Largest shed dimension is 13.5 ft by 13.5 ft

Largest Area is 182.25 ft²

Step-by-step explanation:

Given that;

Perimeter = 54 ft

P = 2( L + B ) = 54ft

L + B = 54/2

L + B = 27 ft

B = 27 - L ------------Let this be equation 1

Area A = L × B

from equ 1, B = 27 - L

Area A = L × ( 27 - L)

A = 27L - L²

for Maxima or Minima

dA/dL = 0

27 - 2L = 0

27 = 2L

L = 13.5 ft

Now, d²A/dL² = -2 < 0

That is, area is maximum at L = 13.5 using second derivative test

B = 27 - L

we substitute vale of L

B = 27 - 13.5 = 13.5 ft

Therefore the Largest shed dimension = 13.5 ft by 13.5 ft

Largest Area = 13.5 × 13.5 = 182.25 ft²

7 0
2 years ago
A company is making a new label for one of their containers. The container is a cylinder that is 9 inches tall and 5 inches in d
nydimaria [60]

Answer:

180.55 in².

Step-by-step explanation:

Data obtained from the question include the following:

Height (h) = 9 in.

Diameter (d) = 5 in

Pi (π) = 3.14

Area of the label =..?

Next, we shall determine the radius.

Diameter (d) = 5 in

Radius (r) =.. ?

Radius (r) = Diameter (d) /2

r = d/2

r = 5/2

r = 2.5 in.

Next, we shall determine the area of the label that needs to be printed to go around the new container by calculating the surface area of the cylinder.

This is illustrated below:

Height (h) = 9 in.

Pi (π) = 3.14

Radius (r) = 2.5 in.

Surface Area (SA) =.?

SA = 2πrh + 2πr²

SA = (2×3.14×2.5×9) + (2×3.14×2.5²)

SA = 141.3 + 39.25

SA = 180.55 in²

The surface area of the cylinder is 180.55 in².

Therefore, the area of the label that needs to be printed to go around the new container is 180.55 in².

5 0
3 years ago
2) In August, Emily's Clothing Store sold 460 shirts with the ratio of short sleeve to long
aivan3 [116]

Answer:

138

Step-by-step explanation:

We know that there are at least 3 short sleeved shirts and there are at least 7 long sleeved shirts. And we know it's in that ratio. So the best way to start this is to divide 460 by 7+3 to get the single unit amount of both shirts.

46 is the single unit amount. So 46 * 3 will get us our short sleeved shirts:

46 * 3 = 138

To check our answer, we'll take 460-138 and divide that by 7 to see if we get 46:

322/7 = 46

So the answer is correct!

4 0
2 years ago
This uses pythagorean theorem
Klio2033 [76]

Step-by-step explanation:

x²=a²+b²

x=√6²+12²

x=√180

x=3√2v

y²=16²+12²

y=√400

y=20

7 0
3 years ago
Read 2 more answers
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