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2 years ago

Can any smart MATH person help me with this will give u brainliest

Mathematics

1 answer:

alukav5142 [94]2 years ago

4 0

Answer: -3/4

Step-by-step explanation:

Since the diagonal line is left to right, it is negative. It is also -3/4x. Hope this helps, please consider making me Brainliest.

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Find the lines slope and a point on the line.

sesenic [268]

Answer:

The slope is 3/4 and a point on the line is (-5,2)

Step-by-step explanation:

This is given in point slope form

y - y1 = m(x-x1)

where m is the slope and (x1,y1) is a point on the line

y-2 = 3/4(x +5)

y-2 = 3/4(x - -5)

The slope is 3/4 and a point on the line is (-5,2)

7 0

3 years ago

Read 2 more answers

N = 9

g100num [7]

Answer:

The p-value is 0.809.

Step-by-step explanation:

In this case we need to perform a significance test for the standard deviation.

The hypothesis is defined as follows:

H₀: σ₀ = 4 vs. Hₐ: σ₀ ≤ 4

The information provided is:

n = 9

s = 3

Compute the Chi-square test statistic as follows:

$\chi^{2}=\frac{(n-1)s^{2}}{\sigma_{0}^{2}}$

$=\frac{(9-1)\cdot (3)^{2}}{(4)^{2}}\\\\=\frac{8\times 9}{16}\\\\=4.5$

The test statistic value is 4.5.

The degrees of freedom is:

df = n - 1

= 9 - 1

= 8

Compute the p-value as follows:

$p-value=P(\chi^{2}_{9}>4.5)=0.809$

*Use a Chi-square table.

Thus, the p-value is 0.809.

7 0

3 years ago

PLS HELP!! For the function f(x)=x+9. Find (f x f^-1)(5)

Karo-lina-s [1.5K]

Answer:

I hope this helps you

Step-by-step explanation:

y=x+9

x=y-9 f^-1 (x)= x-9

x=5 f^-1 (5)=5-9 = -4

f (f^-1))=f (-4)=?

x= -4

f (-4)=-4+9

f (-4)= 5

6 0

3 years ago

Find all solutions in the interval [0, 2π). 2 sin2x = sin x

tester [92]

Answer:

The solutions on the given interval are :

$0$

$\pi$

$\cos^{-1}(\frac{1}{4})$

$-\cos^{-1}(\frac{1}{4})+2\pi$

Step-by-step explanation:

We will need the double angle identity $\sin(2x)=2\sin(x)\cos(x)$ .

Let's begin:

$2\sin(2x)=\sin(x)$

Use double angle identity mentioned on left hand side:

$2\cdot 2\sin(x)\cos(x)=\sin(x)$

Simplify a little bit on left side:

$4\sin(x)\cos(x)=\sin(x)$

Subtract $\sin(x)$ on both sides:

$4\sin(x)\cos(x)-\sin(x)=0$

Factor left hand side:

$\sin(x)[4\cos(x)-1]=0$

Set both factors equal to 0 because at least of them has to be 0 in order for the equation to be true:

$\sin(x)=0 \text{ or } 4\cos(x)-1=0$

The first is easy what angles $\theta$ are $y$ -coordinates on the unit circle 0. That happens at $0$ and $\pi$ on the given range of $x$ (this $x$ is not be confused with the $x$ -coordinate).

Now let's look at the second equation:

$4\cos(x)-1=0$

Isolate $\cos(x)$ .

Add 1 on both sides:

$4 \cos(x)=1$

Divide both sides by 4:

$\cos(x)=\frac{1}{4}$

This is not as easy as finding on the unit circle.

We know $\arccos( )$ will render us a value between $0$ and $2\pi$ .

So one solution on the given interval for x is $x=\cos^{-1}(\frac{1}{4})$ .

We know cosine function is even.

So an equivalent equation is:

$\cos(-x)=\frac{1}{4}$

Apply $\cos^{-1}$ to both sides:

$-x=\cos^{-1}(\frac{1}{4})$

Multiply both sides by -1:

$x=-\cos^{-1}(\frac{1}{4})$

This going to be negative in the 4th quadrant but if we wrap around the unit circle, $2\pi$ , we will get an answer between $0$ and $2\pi$ .

So the solutions on the given interval are :

$0$

$\pi$

$\cos^{-1}(\frac{1}{4})$

$-\cos^{-1}(\frac{1}{4})+2\pi$

5 0

3 years ago

The length of a rectangle is 24 units. Can the perimeter P of the rectangle be 60 units when its width w is 11 units?

marishachu [46]

No it cannot because the perimeter is the sum of all the sides and a rectangle has 4 sides so 24x2 + 11x2 = 70. So the perimeter would be 70 not 60.

Hope this helps :)

5 0

3 years ago