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2 years ago

What statement Correctly describes his solution?

Mathematics

1 answer:

Roman55 [17]2 years ago

5 0

Answer:

(1) option is correct .

Step-by-step explanation:

$2x^2-7x-15$

$=(2x+3)(x-5)$

$=2x^2-10x+3x-15$

which is the equation in the question.

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A ladybugs length measures 2cm express this measurement in meters explain your thinking include an equation with an exponent in

Ksivusya [100]

All we really need to do here is to convert 2 cm to meters. There are 100 cm in 1 meter, so the appropriate cm to meters conversion factor is

1 meter
-----------
100 cm

Thus,

2 cm 1 m
-------- * ----------- = (1/50) m = 0.02 m or 2.0*10^(-2) m (answer)
1 100 cm

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3 years ago

Jean transformed a point by using the rule (x,y)(x-6,y+8) the image point is (-4,1) which point is the pre image

Xelga [282]

To find the pre image you need to back track on the image. To get to the image you used (x-6,y+8). Now you need to use the exact opposite to get back to the pre image. For this you would change the signs to look like (x+6,y-8). Now we just apply this to (-4,1).

(-4+6,1-8)

(2,-7) should be the pre image point.

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3 years ago

Read 2 more answers

A code is formed using four of these letters: A, B, I, K, N, O, and T. (Note that the order of the letters in the code matters;

oksano4ka [1.4K]

To answer this question, use permutation since the order of the letter matters. There are 7 letters and only 4 are to be used for the code. This is a permutation of 7 taken 4 (7P4) which is equal to 840. Thus, the sample space is 840.
For the next questions, there are 3 vowels for as the first letter, only 6 letters are available for the second, 5 on the next, and 4 on the last. Multiplying these numbers give 360. To solve for probability, divide this number with the sample space. Thus, the answer is 3/7.

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3 years ago

For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to

erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

z is equal to 1.645

z = (x-μ)/ $\frac{S}{\sqrt{n} }$

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/ $\frac{3.8}{\sqrt{50} }$

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z = (9.18402 - 9.8)/ $\frac{3.8}{\sqrt{50} }$

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

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2 years ago

Which of the following regarding the power of a significance test is/are correct? Select all that apply.As the effect size incre

Tanya [424]

According to the theory on the effect size the following statements are correct:

As the standard deviation increases, the power of the test increases. An increment of the standard deviation means that a larger sample size is required for the test and a larger sample size implies that the power increases, which means that as the standard deviation increases the power also increases.

As the sample size increases, the power of a test increases. When the sample size increases the amount of information increases, this means that the probability of rejecting H0 given that H0 is false increases. In other words, the probability that the significance test performs according to reality is larger.

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3 years ago