Answer: Conjecture: There is no triangle with side lengths N, 2N, and 3N (where N is a positive real number)
Proof:
We prove this by contradiction: Suppose there was an N for which we can construct a triangle with side lengths N, 2N, and 3N. We then apply the triangle inequalities tests. It must hold that:
N + 2N > 3N
3N > 3N
3 > 3
which is False, for any value of N. This means that the original choice of N is not possible. Since the inequality is False for any value of N, there cannot be any triangle with the given side lengths, thus proving our conjecture.
1st decimal place=tenth
2nd=hundreth
to round, you look at the place after it
so 13.8924439894 to tenth
look untill hundreth
13.89
if hundreth<u>></u>5, round tenth up
if hundreth place<5 leave tenth as is
13.89
9<u>></u>5
round up
8+1=9
13.9 is to theh tenth
Answer:
8.89 feet
Step-by-step explanation:
The square of the side length is 79 ft², so the side length is the square root of that:
√(79 ft²) ≈ 8.88819 ft ≈ 8.89 ft
2 because the equation can be reduced to: 8.0 x 10^4.
13.5 because 4.5 times 3 is 13.5