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svlad2 [7]
1 year ago
14

A contractor is building a pool labeled ABCD on the plans. If AC = 5y + 6 and BD = 8y-3, what value of y ensures the pool is a r

ectangle?
-9
09
O-3
O3
Mathematics
1 answer:
KIM [24]1 year ago
3 0

The value of y that ensures the pool is a rectangle is 3. Option D

<h3>How to determine the value</h3>

The formula for perimeter of a rectangle is expressed as;

Perimeter = 2 ( length + width)

It is important to note that parallel sides of a rectangle are congruent, that is, they are equal.

Given the sides as;

  • AC = 5y + 6
  • BD = 8y-3

5y + 6 = 8y -3

collect like terms

5y - 8y = -3 - 6

-3y = -9

Make 'y' the subject

y = 3

Thus, the value of y that ensures the pool is a rectangle is 3. Option D

Learn more about rectangles here:

brainly.com/question/25292087

#SPJ1

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Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, as shown colon
Nadusha1986 [10]

Answer:

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}  where a\geqslant 0"

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Step-by-step explanation:

Given that " Sadie simplified the expression StartRoot 54 a Superscript 7 b cubed EndRoot, where a greater-than-or-equal-to 0, "

It can be written as \sqrt{54a^7b^3} where a\geqslant 0

The given expression is \sqrt{54a^7b^3} where a\geqslant 0

To find Sadie's error and explain the correct answer :

Sadie's steps are

\sqrt{54a^7b^3}  where a\geqslant 0

=\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b}

=3ab\sqrt{6a^5b}

<h3>\sqrt{54a^7b^3}=3ab\sqrt{6a^5b} where a\geqslant 0</h3><h3><u>Now corrected steps are</u></h3>

\sqrt{54a^7b^3}  where a≥0

=\sqrt{(9\times 6)(a^{6+1})(b^{2+1})

=\sqrt{(3^2\times 6)(a^6.a^1)(b^2.b^1) (by using the identity a^{m+n}=a^m.a^n

=\sqrt{3^2\times 6\times ((a^3)^2.a)(b^2.b) (by using the identity a^{mn}=(a^m)^n )

=3ab\sqrt{6ab}

Therefore \sqrt{54a^7b^3}=3ab\sqrt{6ab}  where a\geqslant 0

<h3>The correct answer is 3ab\sqrt{6ab} where a\geqslant 0</h3>

Sadie's error is " she made error in step 2 =\sqrt{3^2\times 6\times a^2\times a^5\times b^2\times b} " where a\geqslant 0

Because she made error in splitting the powers to simplify the square root

<h3>Therefore the correct answer for Sadie's expression is 3ab\sqrt{6ab} where a\geqslant 0</h3>
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