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3 years ago

In the first stage of cellular respiration, very little energy is released. True or False?

Mathematics

1 answer:

riadik2000 [5.3K]3 years ago

5 0

Answer:

True, its releases enough energy to produce two molecules of ATP for every molecule of glucose that is broken down.

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(2y^3+5y^2-y+15) ÷ (y-4)

Sveta_85 [38]

ANSWER: 2y^2 + 13y +51 r(219/y-4)

picture explanation too:

8 0

3 years ago

A store sells 8 cans of soup for $22. How much would it cost you to buy 9 cans of soup?It would cost $nothing.

puteri [66]

$24.75

this is because 22 ÷ 8 × 9 is equal to 24.75
this is the correct answer

6 0

3 years ago

Come hither for a brainliest

Likurg_2 [28]

Answer:

x - 10, I believe

Step-by-step explanation:

The differences between the x-values and the y-values are

1) 12 & -12 = 0

2) -4 & 0 = 4

3) 0 & 7 = 7

4) 10 & 0 = -10

Since the question asks which must be A factor of p(x) or the y-value, I would advise to look for the answer that helps you receive one of the differences shown above. That said, I would go with <em>x - 10.</em>

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Does that help?

7 0

3 years ago

Read 2 more answers

A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set

lara [203]

A circle with center $(3,0)$ and radius $5$ has equation

$(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x = 16$

If we substitute $y=2x+k$ in this equation, we have

$x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0$

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

$\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0$

The expression simplifies to

$-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89$

The solutions to the associated equation are

$k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}$

So, the parabola is negative between the two solutions:

$-6-5\sqrt{5}$

8 0

3 years ago

What is the fraction 7, 14 simplest form

goldfiish [28.3K]

Answer:

1 is to 2 is the answer. U.got that

3 0

3 years ago