Answer:
O larger than the object and real
Explanation:
As we know by the formula of mirror
here we know that
so we have
so we have
so magnification is given as
so here we have
so image will be larger than object and real
Hi there!
To solve, we must begin by calculating the total WORK done on the object.
W = F · d (Force · displacement)
Plug in the given values. Remember to convert km to m:
1 km = 1000 m
0.6 km = 600 m
W = 60 · 600 = 36000 J
Now, we can solve for power:
P = W/t
Convert minutes to seconds:
1 min = 60 sec
20 min = 1200 sec
P = 36000/1200 = 30 W ⇒ Choice D.
The correct answer for this question is this one: C) 2.5s. T<span>he period and frequency of a water wave if 4.0 complete waves pass a fixed point in 10 seconds is that 2.5 s
</span>
Here are the following choices:
<span>A) 0.25s
B) 0.40s
C) 2.5s
D) 4.0s</span>
The forces on the y axis are:
N-mgcos(60)=0 , wich becomes
N=mgcos(60)
Rember that the friction force is always contrary to the motion of an object and its formula is f=μ * N
The forces in the x axis are:
-f + mgsin(60)= m * a
-μ*mgcos(60) + mgsin(60)=m*a ,
μ = ( m*a - mgf=μ[sin(60) )/ ( mgcos(90) )
It would be purple. That is why it is the outside of the rainbow:)
