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insens350 [35]
3 years ago
10

A pressure of 400 Pa is applied to an area of 2.5 m2.What force applies this pressure?

Physics
1 answer:
Irina-Kira [14]3 years ago
4 0
F = 400 Pa x 2.5 m2
F = 1 kN
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Why were republicans able to dominate politics from 1860 until 1932?
snow_lady [41]

Answer:First the Republicans were dominant from 1860 to around 1882, then not again until 1920 time 1932. The reason for the first part is the Democratic party started a civil war to keep their slaves and the Democratic party lost that war.

Explanation:

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How can doing work on an object increase its kinetic energy?
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Explanation:

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If a diffraction grating has 3700 lines per cm, what is the spacing d between lines
Sonja [21]
So first we find the gap between the slits by the formula d=1/N 

<span>N is number of lines per metre so 3700 line/cm = 370000 lines/m </span>
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<span>Now we use the formula dsin(angle)=n(wavelength) </span>

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7 0
3 years ago
When you throw a ball up in the air, it travels up and then stops instantaneously before falling back down. At the point where i
Gnoma [55]

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The ball stops instantaneously at the topmost point of the motion.

Explanation:

Assume we have thrown a ball up in the air. For that we have given a force on the ball and it acquires an initial velocity in the upward direction.

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The two forces acting in the downward direction reduces its speed continuously and it becomes zero at the topmost point.

4 0
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Two satellites are in circular orbits around a planet that has radius 9.00x10^6 m. One satellite has mass 53.0 kg , orbital radi
Andreas93 [3]

Answer:

The orbital speed of this second satellite is 5195.16 m/s.

Explanation:

Given that,

Orbital radius of first satellite r_{1}= 8.20\times10^{7}

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Mass of first satellite m_{1}=53.0\ kg

Mass of second satellite m_{2}=54.0\ kg

Orbital speed of first satellite = 4800 m/s

We need to calculate the orbital speed of this second satellite

Using formula of orbital speed

v=\sqrt{\dfrac{GM}{r}}

From this relation,

v_{1}\propto\dfrac{1}{\sqrt{r}}

Now, \dfrac{v_{1}}{v_{2}}=\sqrt{\dfrac{r_{2}}{r_{1}}}

v_{2}=v_{1}\times\sqrt{\dfrac{r_{1}}{r_{2}}}

Put the value into the formula

v_{2}=4800\times\sqrt{\dfrac{ 8.20\times10^{7}}{7.00\times10^{7}}}

v_{2}=5195.16\ m/s

Hence, The orbital speed of this second satellite is 5195.16 m/s.

4 0
3 years ago
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