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inn [45]
2 years ago
14

Calculate the molality of a solution containing 14. 3 g of nacl in 42. 2 g of water

Chemistry
1 answer:
Dahasolnce [82]2 years ago
8 0

Answer:

5.80 M

Explanation:

In this problem, the solute is NaCl and the solvent is water. To find the molality, you need to (1) convert grams NaCl to moles NaCl (via molar mass), then (2) convert grams H₂O to kilograms H₂O, and then (3) calculate the molality (via molality equation). The final answer should have 3 sig figs to match the sig figs of the given values.

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

14.3 grams NaCl                1 mole
--------------------------  x  ------------------------  =  0.245 moles NaCl
                                     58.443 grams

(Step 2)

1,000 g = 1 kg

42.2 grams H₂O                 1 kg
--------------------------  x  -----------------------  =  0.0422 kg H₂O
                                      1,000 grams

(Step 3)

Molality = moles solute / mass solvent (kg)

Molality = 0.245 moles NaCl / 0.0422 kg H₂O

Molality = 5.80 M

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Answer:

21.4 L

Explanation:

Given data:

Volume of carbon dioxide produced = ?

Volume of oxygen  = 37.4 L

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L

Now we will compare:

                              O₂             :              CO₂    

                              156.9         :              89.66

                                37.4         :             89.66/156.9×37.4 = 21.4 L

So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.

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3 years ago
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Answer:

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Answer:

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A conversion factor is used to change the units of a measured quantity without changing its value.

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The number of molecules in 1.0 mole of H2O is _____ as in one mole of O2.
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The volume increases when the balloon temperature increases.

<u>Explanation:</u>

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And the room temperature is 25°C which is converted into Kelvin as 273 + 25 = 298 K.

249 K is below room temperature.

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As the balloon temperature increases, the volume also increases.

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