Which of the analogies below is a location-based analogy?

Be sure to answer all parts. Propane (C3H8) is a minor component of natural gas and is used in domestic cooking and heating. (a)

Leokris [45]

Answer:

For a: The balanced chemical equation is given below.

For b: The mass of carbon dioxide produced will be $1.07\times 10^3g$

Explanation:

For a:

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor can be destroyed but it can only be transformed from one form to another form.

This law also states that the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side.

For the given reaction, the balance chemical equation follows:

$C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$

All the substances are present in gaseous state.

For b:

By Stoichiometry of the reaction:

1 mole of propane gas produces 3 moles of carbon dioxide gas.

So, 8.11 moles of propane gas will produce = $\frac{3}{1}\times 8.11=24.33mol$ of carbon dioxide gas.

Now, calculating the mass of carbon dioxide using equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 24.33 mol

Putting values in above equation, we get:

$24.33mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=1070.52g$

Hence, the amount of $CO_2$ produced in the given reaction and expressed in scientific notation is $1.07\times 10^3g$

3 0

4 years ago

How many moles of potassium sulfate are present in a sample that weighs 45.8g?

Nikitich [7]

Answer:

0.263 mol

Explanation:

K2SO4 - potassium sulfate

Molar mass (K2SO4) = 2*39.0983 + 32.065 + 4*15.9994 =

= 174.2592≈174.26 g/mol

45.8 g * 1 mol/174.26 g = 0.263 mol

5 0

3 years ago

In the nuclear transmutation, 168O (?, α)137N, what is the bombarding particle? In the nuclear transmutation, O (?, )N, what is

xeze [42]

Answer:

The bombarding particle is a Proton

Explanation:

A Nuclear transmutation reaction occurs when radioactive element decay, usually converting them from one element/isotope into another element. Transmutation is the process which causes decay, generally, alpha or beta.

¹⁶₈O(P,alpha) ¹³₇N, can be written as

¹⁶₈O + x goes to ¹³₇N + ⁴₂He

Where x can be anything, balancing the equation in order to give us the correct amount of proton number and nucleus number

16 + x = 13 + 4

x = 17 – 16 = 1, Hence we can say that x = ¹₁P

¹⁶₈O + ¹₁P goes to ¹³₇N + ⁴₂He

Here we can clearly see the bombarding particle is ¹₁P (proton). The ejected particle being ⁴₂He which is also known as an alpha particle

5 0

4 years ago

What is the half-life for the first order decay of 14C according to the reaction, 146C — 147N +e- ?

m_a_m_a [10]

Answer:

5727 years or 5730 (rounded to match 3 sig figs) whichever one your teacher prefers

Explanation:

First Order decay has a half life formula of Half Life = Ln (2) / k = 0.693/K

Half-life = 0.693/k = 0.693/1.21 x10-4 = 5727 years or 5730 (rounded to match 3 sig figs)

This should be correct because if you google the half-life of 14 C it is ~ 5700 years

8 0

3 years ago

How many unpaired electrons are present in the ground state of the atoms in group 6a(16)?

____ [38]

Lets take one element from Group 6A, Let it be oxygen, The electronic configuration of Oxygen is as follow,

O = 8 = 1s², 2s², 2px², 2py¹, 2px¹

There are 6 electrons in the valence shell of elements present in Group 6A. The unpaired electrons in 2px and 2py are involved in forming covalent bond, while the pair of electrons in 2s and 2px are unshared and act as lone pair of electrons.

Result:
There are TWO unpaired electrons present in the ground state of Group 6A elements.

5 0

3 years ago