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3 years ago

A5 gram ball has a volume of 2.5 milliliters. What is the density of the ball?

Chemistry

1 answer:

DENIUS [597]3 years ago

8 0

Answer:

2 g/mL

Explanation:

The following data were obtained from the question:

Mass (m) = 5 g

Volume (V) = 2.5 mL

Density (D) =.?

Density is simply defined as the mass of substance per unit volume of the substance. Mathematically, it is expressed as:

Density (D) = mass (m) /volume (V)

D = m/V

With the above formula, we can obtain the density of the ball as follow:

Mass (m) = 5 g

Volume (V) = 2.5 mL

Density (D) =.?

D = m/V

D = 5/2.5

D = 2 g/mL

Therefore, the density of the ball is 2 g/mL.

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The Bohr model is an inaccurate model because there is no way to measure the exact position or location of an electron in an atom.

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Passing an electric current through a sample of water (H2O) can cause the water to decompose into hydrogen gas (H2) and oxygen g

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<u>Answer:</u> The mass of water that must be reacted is 56.28 grams.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

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$\text{Moles of oxygen}=\frac{50g}{32g/mol}=1.5625mol$

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$2H_2O\rightarrow 2H_2+O_2$

By Stoichiometry of the reaction:

1 mole of oxygen is produced when 2 moles of water is reacted.

So, 1.5625 moles of oxygen is produced when = $\frac{2}{1}\times 1.5625=3.125mol$ of water is reacted.

To calculate the mass of water, we use equation 1:

Moles of water = 3.125 moles

Molar mass of water = 18.01 g/mol

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What mass of iron is needed to react with sulfur in order to produce 96 grams of

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Answer:

51.69 g of Fe

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

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Mass of Fe₂S₃ from the balanced equation = 1 × 208 = 208 g

SUMMARY:

From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

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From the balanced equation above,

112 g of Fe reacted to produce 208 g of Fe₂S₃.

Therefore, Xg of Fe will react to produce 96 g of Fe₂S₃ i.e

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