Answer:
4.5 feet = 1.5 yards
Step-by-step explanation:
1 yard equals 3 feet
Then:
1 ----- 3
x -----4.5
Hope this helps
Factor by grouping. Group up the terms into pairs, factor each pair, then factor out the overall GCF.
x^3 + 2x^2 - 16x - 32
(x^3 + 2x^2) + (-16x-32) ... pair up terms
x^2(x + 2) + (-16x - 32) ... factor x^2 from the first group
x^2(x + 2) - 16(x + 2) ... factor -16 from the second group
(x^2 - 16)(x + 2) .... factor out (x+2)
(x - 4)(x + 4)(x + 2) .... Use the difference of squares to factor x^2-16
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The original expression completely factors to (x - 4)(x + 4)(x + 2)
The three factors are x - 4 and x + 4 and x + 2
From the 64 values in the table on the left, count how many fall within the given ranges under the "classes" column in the table on the right. The "frequency" is the number of values in the data that belong to a given "class".
For example, "< -16.0" means "values below -16.0". Only one number satisfies this: -16.2 (first row, third column). So the frequency for this class is just 1.
Then for the range "-15.9 - 13.0", which probably means "numbers between 15.9 and -13.0, inclusive", the frequency is 0 because every number in the table is larger than the ones in this range.
And so on.
Answer:
Step-by-step explanation:
Let s represent the son's age now. Then s+32 is the father's age. In 4 years, we have ...
5(s+4) = (s+32)+4
5s +20 = s +36 . . . . . eliminate parentheses
4s = 16 . . . . . . . . . . . . subtract s+20
s = 4
The son is now 4 years old; the father, 36.
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<em>Alternate solution</em>
In 4 years, the ratio of ages is ...
father : son = 5 : 1
The difference of their ages at that time is 5-1 = 4 "ratio units". Since the difference in ages is 32 years, each ratio unit must stand for 32/4 = 8 years. That is, the future age ratio is ...
father : son = 40 : 8
So, now (4 years earlier), the ages must be ...
father: 36; son: 4.
