Question

Suppose a is jointly proportional to b and c. if a=4 when b=8 and c = 9, then what is a when b=2 and c=18

Answer 1

From the given information, a exists jointly proportional to b and c.

then $a \propto b c$

Therefore, the value of a exists 2.

What is the value of a?

Given, a exists jointly proportional to b and c.

$a \propto b c$

Taking K as the constant of proportionality.

a = K b c

For b = 8 and c = 9, the value of a = 4

4 = K(8)(9)

4 = 72 K

Dividing the equation by 72, we get

$K=\frac{1}{18}$

Using the value of K in the equation:

$a=\frac{b c}{18}$

Substitute the values of b = 2 and c = 18, in the above equation

$a=\frac{2 \times 18}{18}$

a = 2

Therefore, the value of a exists 2.

To learn more the value of x refers to:

brainly.com/question/11874663

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