Question

H^-16/h^x=1/h^24 can someone help me please

Answer 1

Given:

Consider the equation is

$\dfrac{h^{16}}{h^x}=\dfrac{1}{h^{24}}$

To find:

The value of x.

Solution:

We have,

$\dfrac{h^{-16}}{h^x}=\dfrac{1}{h^{24}}$

Using properties of exponents, we get

$h^{-16-x}=h^{-24}$       $[\because \dfrac{a^m}{a^n}=a^{m-n},a^{-n}=\dfrac{1}{a^n}]$

On comparing both sides, we get

$-16-x=-24$

Add 16 on both sides.

$-x=-24+16$

$-x=-8$

Multiply both sides by -1.

$x=8$

Therefore, the value of x is 8.