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3 years ago

What would occur if you were to replace the bulb in the circuit with a much brighter bulb?

Physics

2 answers:

Sophie [7]3 years ago

8 0

A most energy would be transferred from electrical energy to light energy
I took the test

mylen [45]3 years ago

7 0

More energy would be transferred from electrical to light.

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A 2-kg sample of a metal increases in temperature by 20°C when heated on a stove for 3 minutes. Can you predict what will happen

padilas [110]

Answer:

Explanation:

7 0

3 years ago

A 40 kg bear slides, from rest, 14 m down a lodgepole pine tree, moving with a speed of 3.7 m/s just before hitting the ground.

antiseptic1488 [7]

Answer:

A. -5488J

B. 273.8J

C. 372.44N

Explanation:

Given:

m = 40kg

h = 14 m

v= 3.7 m/s

Part(a)

The change in the potential energy of the bear Earth system during the slide

AU = -mgh = -40(9.8) (14) = -5488 J

Part(b)

The kinetic energy of the bear just before hitting the ground is

Ks 1/2 mV^2= (40)(3.7)2 = 547.6 /2 = 273.8J

Part(c)

The change in the thermal energy of the system due to friction is

AEth = fxh=-(AK +AU) = 5488– 273.8 = 5214.2 J

The average frictional force that acts on the sliding bear is

F = Eth / 14= 5214.2/14 =372.44N

4 0

3 years ago

Read 2 more answers

A typical person's eye is 2.5 cm in diameter and has a near point (the closest an object can be and still be seen in focus) of 2

Paraphin [41]

Answer:

2.27 cm

2.5 cm

Explanation:

u = Object distance = 25 cm

v = Image distance = 2.5 cm

f = Focal length

Lens Equation

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{25}+\frac{1}{2.5}\\\Rightarrow \frac{1}{f}=\frac{11}{25}\\\Rightarrow f=\frac{25}{11}=2.27\ cm$

The minimum effective focal length of the focusing mechanism of the typical eye is 2.27 cm

when $u=\infty$

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{\infty}+\frac{1}{2.5}\\\Rightarrow \frac{1}{f}=\frac{1}{2.5}\\\Rightarrow f=\frac{2.5}{1}=2.5\ cm$