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nikitadnepr [17]
4 years ago
8

As outlaws escape in their getaway ear, which goes 3/4 c, the police officer fires a bullet from a pursuit ear, which only goes

1/2 c. The muzzle velocity of the bullet (relative to the gun) is 1/3 c. Does the bullet reach its target according to Galileo according to Einstein?
Physics
1 answer:
Mariulka [41]4 years ago
7 0

Answer:

a) Bullet will hit

b) Bullets will not hit

Explanation:

Given:

The velocity of the bullet, u = \frac{1}{3}c in the rest frame of the bullet pursuit car

The velocity of the original frame of reference, v = -\frac{1}{2}c with respect to the pursuit car.

Now, according to the Galileo

the velocity of the bullet in the original frame of reference (u') will be

u' = u - v

on substituting the values we get

u' = \frac{1}{3}c-(-\frac{1}{2}c)

or

u' = \frac{1}{3}c+\frac{1}{2}c

or

u' = \frac{5}{6}c

since this velocity ( \frac{5}{6}c) is greater than the ( \frac{3}{4}c)

hence,

<u>the bullet will hit</u>

Now, according to the Einstein theory

the velocity of the bullet in the original frame of reference (u') will be

u'=\frac{u-v}{1-\frac{uv}{c^2}}

on substituting the values we get

u'=\frac{\frac{1}{3}c-\frac{1}{2}c}{1-\frac{\frac{1}{3}c\times \frac{1}{2}c}{c^2}}

or

u'=\frac{\frac{5}{6}c}{1-\frac{1}{6}}

or

u'=\frac{5}{7}c

since,

u'=\frac{5}{7}c is less than  ( \frac{3}{4}c), this means that the bullet will not hit

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Find the angle of depression from the top of a lighthouse 250 feet above water level to the water line of a ship 2.5 miles offsh
Rudik [331]
Height of the lighthouse = 250 feet
Distance of the ship from the shore = 2.5 miles
We already know that
1 mile = 5280 feet
Then
2.5 miles = 5280 * 2.5
               = 13200 feet
Now, to find the angle of depression, we can use the formula
<span>θ = <span>tan<span>−1 </span></span>(13200/250)
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I hope that this is the answer that you were looking for and the answer has come to your desired help. 
4 0
4 years ago
A man walks 30m to the west, then 5m to the east in 45 seconds. What is the average velocity?
solong [7]
1.28m/s the velocity is found by distance/time.
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How many days sun rises in a year​
Lana71 [14]

Answer:

365

Explanation:

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43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a
olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N

The frictional force that acts on the sliding bear is 378.47166 N

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