Answer:
The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C is 45,360 J
Explanation:
The given parameters for the refrigeration unit and the ice cream are;
The power of the refrigeration unit = 120 J/s
The mass of the liquid ice cream, m = 0.6 kg
The initial temperature of the liquid ice cream, T₁ = 20°C
The freezing point temperature of the ice cream, T₂ = -16°C
The specific heat capacity of the ice cream, c = 2,100 J/kg⁻¹·°C⁻¹
The amount of heat energy that must be removed from the mixture to cool it to its freezing point, ΔQ, is given as follows;
ΔQ = m × c × ΔT
Where;
ΔT = T₁ - T₂
∴ ΔQ = m × c × (T₁ - T₂)
Therefore, by substituting the known values, we have;
ΔQ = 0.6 × 2,100 × (20 - (-16)) = 45,360
The amount of heat energy that must be removed from the mixture to cool it to its freezing point, of -16°C = ΔQ = 45,360 J.
