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Dvinal [7]
2 years ago
9

A light ray is traveling from medium a to medium b. as it enters medium b, it bends toward the normal. what can you say about th

e speed of light in the medium? a. the speed of light in medium a is greater than that in medium b. b. the speed of light in medium a is less than that in medium b. c. the speed of light in medium a is the same as in medium b. d. the speed of light in medium b is zero.
Physics
1 answer:
Eva8 [605]2 years ago
7 0

The speed of light in medium a is greater than that in medium b.

<h3></h3><h3>What is refraction?</h3>

The redirection of a wave as it travels through one medium and into another is called refraction. A change in the medium or a change in the wave's speed might both result in the redirection. Although refraction of light waves is the most often seen phenomena, refraction may also occur with sound waves and water waves. The wave speed change and the initial wave propagation direction in relation to the wave speed change both affect how much a wave is refracted.

Refraction of light is governed by Snell's rule, which says that for a given set of media, the ratio of the sines of the angle of incidence and angle of refraction are equal to the phase velocities (v1/v2) or, alternatively, the refractive indices (n2/n1) of the two media.

{\displaystyle {\frac {\sin \theta _{1}}{\sin \theta _{2}}}={\frac {v_{1}}{v_{2}}}={\frac {n_{2}}{n_{1}}}}

A light ray is traveling from medium a to medium b. as it enters medium b, it bends toward the normal. it states that the medium b is denser than medium a, which results in the bending of the ray of light. as a result we can say that speed of light in medium b is less.

to learn more about refraction go to -

brainly.com/question/10769980

#SPJ4

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Answer:

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Explanation:

if n1 = 1.33 is the refractive index of water and ∅1 is the angle at which the flashlight shine beneath the water, and n2 = 1.0 is the refractive index of air and ∅2 is the angle the flashlight leaves the water.

Then, according to Snell's law :

n1×sin(∅1) = n2×sin(∅2)

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Therefore, the flashlight leaves the water at an angle of 51.77°.

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