Answer:
What are we supposed to find, if it is kinetic energy then this is the solution.
K.E=1/2mv^2
K.E= kinetic energy
M=mass
V=velocity
K.E =0.5*55*0.6^2
K.E=9.9J
Explanation:
Answer:
a) 5m/s2
b) 4 sec
c) 6 sec
d) 90 m
e) Answer in the file attached as it is a graph
Explanation:
This question can be solved using equations of motion. The two equations are:
2(a)(s) = v² – u²
v = u + (a)(t)
a = acceleration
s = distance
v = final velocity
u = initial velocity
t = time
a) Given final velocity = 50m/s and initial velocity = 30 m/s for 160m journey
Using 2(a)(s) = v² - u²
2(a)(160) = 50² – 30²
320 (a) = 2500 - 900
a = 1600/320
a = 5m/s²
b) The acceleration remains constant throughout so we can use it in this part as well.
Using v = u + (a)(t)
50 = 30 + (5)(t)
t = 4 sec
c) The acceleration remains constant throughout so we can use it in this part as well. Now the initial velocity will be 0m/s and final will be 30m/s
Using v = u + (a)(t)
30 = 0 + 5(t)
t = 6 sec
d) The acceleration remains constant throughout so we can use it in this part as well. Now the initial velocity will be 0m/s and final will be 30m/s
Using 2(a)(s) = v² - u²
2(5) (s) = 30² – 0²
10(s) = 900
s = 90 m
e) Graphs are attached as image
If you are talking about asexual reproduction, then the chances of getting an A gamete is 100% since the parent has AA, so there is no other possibility
The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
- <em>Tension on each strand of silk, T = 1.42 N</em>
- <em>Angle of inclination of each strand, θ = 75⁰</em>
The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;
where;
- W is the weight of the seashell
The weight of the seashell is calculated as;
The mass of the seashell is calculated as follows;
Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
Learn more about equilibrium forces here: brainly.com/question/8045102
(a) -17 cm
Magnification equation:
where
is the size of the image
is the size of the object
is the distance of the image from the mirror
is the distance of the object from the mirror
In this problem, we have:
p = 51 cm (the object is 51 cm in front of the mirror)
So, we can find q, the image distance:
and the negative sign means the image is virtual.
(b) -25.5 cm
Mirror equation:
where
p = 51 cm
q = -17 cm
Substituting and re-arranging the equation, we find the focal length of the mirror:
and the negative sign is due to the fact it is a convex mirror.