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user100 [1]
2 years ago
13

PLEASE HELP!!!!!!!! NEED DONE SOON!!!

Physics
2 answers:
Ivanshal [37]2 years ago
7 0
The object is decelerating as time goes by
zhannawk [14.2K]2 years ago
4 0

Answer:

the object is decelerating

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3 years ago
Find the velocity of a baseball thrown 78 m from third base to first base in 30 sec​
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2 years ago
A hockey puck slides off the edge of a platform with an initial velocity of 20 m/s horizontally. The height of the platform abov
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Answer:

20.96 m/s

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Using the equations of motion

y = uᵧt + gt²/2

Since the puck slides off horizontally,

uᵧ = vertical component of the initial velocity of the puck = 0 m/s

y = vertical height of the platform = 2 m

g = 9.8 m/s²

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2 = (0)(t) + 9.8 t²/2

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t = 0.639 s

For the horizontal component of the motion

x = uₓt + gt²/2

x = horizontal distance covered by the puck

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g = 0 m/s² as there's no acceleration component in the x-direction

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For the final velocity, we'll calculate the horizontal and vertical components

vₓ² = uₓ² + 2gx

g = 0 m/s²

vₓ = uₓ = 20 m/s

Vertical component

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