This question involves the concepts of projectile motion and launch speed.
(a) The initial launch speed of the projectile is "100 m/s".
(b) The launch angle of the projectile is "53.13°".
<h3>(a) LAUNCH SPEED</h3>
A projectile motion is a motion that takes place on both x and y axes, simultaneously. In this motion the initial launch speed is given by the following formula:
where,
= initial launch speed = ?
= horizontal component of initial launch speed = 60 m/s
= vertical component of initial launch speed = 80 m/s
Therefore,
<h3>(b) LAUNCH ANGLE</h3>
Launch angle is given by th following formula:
Learn more about the projectile motion here:
brainly.com/question/11049671
Answer:
Explanation:
We have given mass of helium nucleus 
Velocity of helium nucleus 
Momentum of the helium nucleus is given by 
where m is mass and v is velocity
So 
When two plates collide, it is the density that determines which plate comes out on top. <span>The more denser </span>plate<span> subducts (goes under) the less denser </span>plate<span>. Hope this answers the question. Have a nice day. Feel free to ask more questions.</span>
Answer:
T = 10010 N
Explanation:
To solve this problem we must use the translational equilibrium relation, let's set a reference frame
X axis
Fₓ-Fₓ = 0
Fₓ = Fₓ
whereby the horizontal components of the tension in the cable cancel
Y Axis
2
= W
let's use trigonometry to find the angles
tan θ = y / x
θ = tan⁻¹ (0.30 / 0.50 L)
θ = tan⁻¹ (0.30 / 0.50 15)
θ = 2.29º
the components of stress are
F_{y} = T sin θ
we substitute
2 T sin θ = W
T = W / 2sin θ
T = 
T = 10010 N
