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3 years ago

11

HELP ASAP !!! !!!!!!!

2 answers:

Strike441 [17]3 years ago

7 0

The second option - B

icang [17]3 years ago

3 0

Answer:

they are cooler than the rest if the sun

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A +5.0 uC point charge is placed at the 0 cm mark of a meter stick and a -4.0 °C charge is

viva [34]

Answer:

-1.44*10^11v/m

Explanation:

6 0

4 years ago

g A bowling ball with a mass of 3.86 kg and a radius of 0.161 m starts from rest at a height of 2.5 m and rolls down a 48.4 o sl

Fynjy0 [20]

Answer:

$v=1.5m/s$

Explanation:

The gravitational potential energy gets transformed into translational and rotational kinetic energy, so we can write $mgh=\frac{mv^2}{2}+\frac{I\omega^2}{2}$ . Since $v=r\omega$ (the ball rolls without slipping) and for a solid sphere $I=\frac{2mr^2}{5}$ , we have:

$mgh=\frac{mv^2}{2}+\frac{2mr^2\omega^2}{2*5}=\frac{mv^2}{2}+\frac{mv^2}{5}=\frac{7mv^2}{10}$

So our translational speed will be:

$v=\sqrt{\frac{10gh}{7}}=\sqrt{\frac{10(9.8m/s^2)(0.161m)}{7}}=1.5m/s$

6 0

3 years ago

Which of the following are ways in which energy can be transferred to or from a substance?

Gnesinka [82]

Answer:

a

Explanation:

the answer is a because it is feasible

3 0

3 years ago

A horizontal uniform meter stick supported at the 50-cm mark has a mass of 0.50 kg hanging from it at the 20-cm mark and a 0.30

ElenaW [278]

Answer:

70 cm

Explanation:

0.5 kg at 20 cm

0.3 kg at 60 cm

x = Distance of the third 0.6 kg mass

Meter stick hanging at 50 cm

Torque about the support point is given by (torque is conserved)

$0.5(50-20)=0.3(60-50)+0.6x\\\Rightarrow x=\dfrac{0.5(50-20)-0.3(60-50)}{0.6}\\\Rightarrow x=20\ cm$

The position of the third mass of 0.6 kg is at 20+50 = 70 cm

7 0

4 years ago

Read 2 more answers

Purpose of slip rings in ac generators

Leni [432]

I hope this helps you

6 0

3 years ago