Answer:
The number of plums = 4
The number of peaches = 16
The number of nectarines = 1
Step-by-step explanation:
Let the number of peaches be = x
Let the number of nectarines be = y
Let the number of plums be = z
A box of fruit has four times more peaches than plums. This means that
The number of peaches = 4 X the number of plums.
i.e x = 4z
The box has 3 fewer nectarines than plums. This means that
Number of nectarines = number of plums - 3
i.e y = z - 3
If the box contains 21 pieces of fruit, this means that if we sum up all the peaches, nectarines, and plums in the box, we will get 21.
Peaches + Nectarines + Plums = 21
4z + z-3 + z = 21
6z =21 +3
z = 24/6
z = 4
Therefore, the number of plums = 4
The number of peaches = 4 X 4 = 16
The number of nectarines = 4 -3 = 1
Question one:A
Question 2: C
Answer:
The answer is y = 2x - 3.
Step-by-step explanation:
Move 2x to the right side of the equation by adding it to both sides:
-2x + y + 3 = 0
<u>+ 2x + 2x</u>
y + 3 = 2x
Then, move 3 to the right side of the equation by subtracting it form both sides:
y + 3 = 2x
<u> - 3 - 3</u>
y = 2x - 3
Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
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