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FromTheMoon [43]
1 year ago
15

Balance the following skeleton reactions and identify the oxidizing and reducing agents:(b) Mn²⁺(aq) + BiO₃⁻(aq) → MnO₄⁻(aq) + B

i³⁺(aq) [acidic]
Chemistry
1 answer:
amm18121 year ago
5 0

The balanced skeleton reactions are given below

2Mn²⁺(aq) +5BiO₃⁻(aq) +  14H^{+}(aq)  →  2MnO₄⁻(aq) + 5Bi³⁺(aq) + 7H_{2}O(l)

The oxidising agent and  reducing agents are Bi and Mn.

There are following steps involve in balance redox reaction in acidic medium .

  • First divide the reaction into two half reactions .
  • Balance the elements other than oxygen and hydrogen atom.
  • Balance the oxygen atom by adding H_{2}O on that side where number of oxygen  atom is less .
  • Balance the hydrogen atom by adding H^{+} on another side of in which water attached .
  • Balance the charge by adding e^{-} .
  • Add the two half reaction  .

The species which reduces the other species in the redox reaction is called oxidizing agent . Similarly , the species which oxidize the other species in the redox reaction  is called reducing agent .

To learn more about reducing agents please click here ,

brainly.com/question/2890416?

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Calculate the grams of ethane present in a sample containing 0.4271 moles if the molar mass of ethane is 30.067 g/mol.
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The grams of ethane present in a sample containing 0.4271 mole is 12.84 g

<h3>Description of mole </h3>

The mole of a substance is related to it's mass and molar mass according to the following equation

Mole = mass / molar mass

With the above formula, we can obtain the mass of ethane. Details below

<h3>How to determine the mass of ethane</h3>

The following data were obtained from the question:

  • Mole of ethane = 0.4271 mole
  • Molar mass of ethane = 30.067 g/mol
  • Mass of ethane =?

The mass of ethane present in the sample can be obtained as follow:

Mole = mass / molar mass

Cross multiply

Mass = mole × molar mass

Mass of ethane = 0.4271 × 30.067

Mass of ethane = 12.84 g

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