The balanced equation for the neutralisation reaction is as follows
2HNO₃ + Ba(OH)₂ ---> Ba(NO₃)₂ + 2H₂O
stoichiometry of HNO₃ to Ba(OH)₂ is 2:1
number of Ba(OH)₂ mol present - 0.108 mol
1 mol of Ba(OH)₂ neutralises 2 mol of Ba(OH)₂
therefore 0.108 mol of Ba(OH)₂ neutralises - 2 x 0.108 mol = 0.216 mol of HNO₃
32L —> 32000g —> 727.116 Moles (rounded)
Answer:
V= 48L
Explanation:
Moles of N2 = m/M = 30/28= 1.07moles
From the equation of reaction
N2 +3H2 → 2NH3
1mole of N2 produces 2mole of NH3
Hence
1.07moles will produce 1.07×2= 2.14 moles
At STP, 1mole occupy 22.4L
Hence volume of N2 produced = 2.14×22.4= 48 L
Answer:
John Dalton
Explanation:
John Dalton (1766-1844) is the scientist credited for proposing the atomic theory. This theory explains several concepts that are relevant in the observable world.
