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Mekhanik [1.2K]
3 years ago
12

At which region of a state’s geology would an earthquake be more likely

Chemistry
1 answer:
nadezda [96]3 years ago
6 0

Around a transform boundary between two plates that slide past each other.

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A meteor falls toward Earth's surface. Given that the acceleration due to
ICE Princess25 [194]

Answer:

E = 147000  J

Explanation:

Given that,

The mass of meteor, m = 50 kg

The altitude of the meteor, h = 300 m

We need to find the potential energy of the meteor. The formula for the potential energy is given by :

E=mgh

Put all the values,

E=50\times 9.8\times 300\\\\E=147000\ J

So, the required potential energy is equal to 147000  J.

4 0
3 years ago
Question 8 (10 points)
I am Lyosha [343]

Answer:

positively charged elctrons

4 0
3 years ago
Read 2 more answers
GIVING BRAINLIEST AND THE REST OF MY POINTS!!!!! :D
Alik [6]
It’s d I did this before
6 0
3 years ago
What is the pH of a solution of 0.800 M KH2PO4, potassium dihydrogen phosphate?
Nookie1986 [14]
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
x = [OH⁻] = 1.03 x 10⁻⁶ M
pOH = - log (1.03 x 10⁻⁶) = 5.99
pH = 14 - pOH = 14 - 5.99 = 8.01 



3 0
3 years ago
What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

8 0
3 years ago
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