Critical thinking means that you should question everything that you read and hear and you should also verify your information. You should not just accept the first possible answer without questioning or verifying it.
So the correct answer is:
c. implementing the first solution to a problem identified
Answer:
-0.79 J
Explanation:
We are given that
![q_1=3.4\mu C=3.4\times 10^{-6} C](https://tex.z-dn.net/?f=q_1%3D3.4%5Cmu%20C%3D3.4%5Ctimes%2010%5E%7B-6%7D%20C)
![1\mu C=10^{-6} C](https://tex.z-dn.net/?f=1%5Cmu%20C%3D10%5E%7B-6%7D%20C)
![q_2=-4.9\mu C=-4.9\times 10^{-6} C](https://tex.z-dn.net/?f=q_2%3D-4.9%5Cmu%20C%3D-4.9%5Ctimes%2010%5E%7B-6%7D%20C)
![x_1=0.125,y_1=0](https://tex.z-dn.net/?f=x_1%3D0.125%2Cy_1%3D0)
![x_2=0.280,y_2=0.235](https://tex.z-dn.net/?f=x_2%3D0.280%2Cy_2%3D0.235)
We have to find the work done by the electric force on the moving point charge.
![r_1=\sqrt{x^2_1+y^2_1}=\sqrt{(0.125)^2+0}=0.125](https://tex.z-dn.net/?f=r_1%3D%5Csqrt%7Bx%5E2_1%2By%5E2_1%7D%3D%5Csqrt%7B%280.125%29%5E2%2B0%7D%3D0.125)
![r_2=\sqrt{(0.280)^2+(0.235)^2}=0.366](https://tex.z-dn.net/?f=r_2%3D%5Csqrt%7B%280.280%29%5E2%2B%280.235%29%5E2%7D%3D0.366)
Work done,![W=kq_1q_2(\frac{1}{r_1}-\frac{1}{r_2})](https://tex.z-dn.net/?f=W%3Dkq_1q_2%28%5Cfrac%7B1%7D%7Br_1%7D-%5Cfrac%7B1%7D%7Br_2%7D%29)
Where ![k=9\times 10^9](https://tex.z-dn.net/?f=k%3D9%5Ctimes%2010%5E9)
Using the formula
![W=9\times 10^9\times 3.4\times 10^{-6}\times(-4.9\times 10^{-6})(\frac{1}{0.125}-\frac{1}{0.366})](https://tex.z-dn.net/?f=W%3D9%5Ctimes%2010%5E9%5Ctimes%203.4%5Ctimes%2010%5E%7B-6%7D%5Ctimes%28-4.9%5Ctimes%2010%5E%7B-6%7D%29%28%5Cfrac%7B1%7D%7B0.125%7D-%5Cfrac%7B1%7D%7B0.366%7D%29)
![W=-0.79 J](https://tex.z-dn.net/?f=W%3D-0.79%20J)
If Fg=mg=ma and, Fg(planetX)=1/5Fg(earth)
then the time would be 5x of the time as gravity is acceleration. So 3.9s*5=19.5s
As the force of gravity is less, then the acceleration of masses is also less, therefore it will take more time for the object to fall by the factor of the force of gravity difference
Answer:
Thickness of Styrofoam insulation is 0.02741 m.
Explanation:
Given that,
Height = 0.25 m
Depth = 0.5 m
Power = 400 W
Temperature = 33°C
We need to calculate the area of Styrofoam
Using formula of area
![A=2(lb+bh+hl)](https://tex.z-dn.net/?f=A%3D2%28lb%2Bbh%2Bhl%29)
Put the value into the formula
![A=2(0.3\times0.5+0.25\times0.5+0.5\times0.3)](https://tex.z-dn.net/?f=A%3D2%280.3%5Ctimes0.5%2B0.25%5Ctimes0.5%2B0.5%5Ctimes0.3%29)
![A=0.85\ m^2](https://tex.z-dn.net/?f=A%3D0.85%5C%20m%5E2)
Inner surface temperature of freezer
![T_{i}=-10°C=263\ K](https://tex.z-dn.net/?f=T_%7Bi%7D%3D-10%C2%B0C%3D263%5C%20K)
Outer surface temperature of freezer
![T_{o}=33+273=306\ K](https://tex.z-dn.net/?f=T_%7Bo%7D%3D33%2B273%3D306%5C%20K)
We need to calculate the thickness of Styrofoam insulation
Using Fourier law,
![q=\dfrac{kA}{L}(T_{o}-T_{i})](https://tex.z-dn.net/?f=q%3D%5Cdfrac%7BkA%7D%7BL%7D%28T_%7Bo%7D-T_%7Bi%7D%29)
![L=\dfrac{kA}{q}(T_{o}-T_{i})](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7BkA%7D%7Bq%7D%28T_%7Bo%7D-T_%7Bi%7D%29)
Put the value into the formula
![L=\dfrac{0.30\times0.85}{400}(306-263)](https://tex.z-dn.net/?f=L%3D%5Cdfrac%7B0.30%5Ctimes0.85%7D%7B400%7D%28306-263%29)
![L=0.02741\ m](https://tex.z-dn.net/?f=L%3D0.02741%5C%20m)
Hence, Thickness of Styrofoam insulation is 0.02741 m.
Answer:
Explanation:
We shall apply law of refraction which is as follows
sin i / sinr = μ , where i is angle of incidence , r is angle of refraction and μ is refractive index
here i = θa = 22.5°
r = θb
μ = 1.77
sin22.5 / sinθb = 1.77
.3826 / sinθb = 1.77
sinθb = .216
θb = 12.5 °.