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jolli1 [7]
3 years ago
15

A motor exerts a force of 12,00N to lift an elevator 8.0m in 7.0secs what is the power produced by the motor?

Physics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

1371.4watt

Explanation:

from power=energy/time

BUT energy=force times distance

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John dragged a wooden block across a table with 4 different surfaces and the results
AnnyKZ [126]

If the surface is rough then the average force needed to move the wooden block will be more as the friction between the surfaces will be more.

Hence, the least force will be required on the smoothest surface and the greatest force will be required for the roughest surface.

a) Hence, the order will be: B > D > A > C

b) When the surface is glued then the force of friction will increase. Hence, it will require more force to move the wooden block on the surface. Hence, the more required will be more than 105 N.

4 0
3 years ago
Suppose there is a sample of xenon in a sealed rectangular container. The gas exerts a total force of 6.05 N perpendicular to on
shtirl [24]

Answer:

<h2> 0.147136N/m²</h2>

Explanation:

Pressure is defines as force exerts by a body per its unit area.

Pressure = Force/Area

Given the total force exerted by the gas = 6.05N

Area of the rectangular container = 0.121 m * 0.201 m = 0.024321m²

Pressure of the sample = 6.05/0.02432

Pressure of the sample = 0.147136N/m²

6 0
4 years ago
A. What is an electric field line?
Lorico [155]

Answer:

Please see below as the answers are self-explanatory

Explanation:

a)

  • A electric field line is an imaginary line, which has the property that the electric field vector is tangent to it at any point. It starts from positive charges (since the electric field by convention it has the direction of the trajectory that would take a positive test charge, so it always goes away from positive charges) and ends in negative charges.

b)

  • Since the potential difference between two points represents the work per unit charge needed for a charge to move between these points, a equipotential surface is the one over which it is not needed to do work to move a charge from any point on the surface to any other point, which means that all points are at the same potential.

c)

  • Equipotential surfaces are not necessarily physical surfaces, they can be defined in vaccum for instance.
  • As an example, any spherical surface concentric with a point charge, is an equipotential surface, and  it can be a real surface or a fictitious one.
7 0
3 years ago
Find the energy in joules required to lift a 55.0 megagram object a distance of 500cm
pantera1 [17]

1,000 grams = 1 kilogram
so 55 megagrams = 55,000 kilograms

100 cm = 1 meter
so 500 cm = 5 meters

Acceleration of gravity on Earth = 9.8 m/s²

Weight = (mass) x (gravity)

========================================

Work = increase in potential energy =

               (weight) x (height) =

             (mass) x (gravity) x (height) =

             (55,000 kg) x (9.8 m/s²) x (5 m) =

                     2,695,000 joules .

5 0
4 years ago
Use the work-energy theorem to determine the force required to stop a 1000 kg car moving at a speed of 20.0 m/s if there is a di
Vlad1618 [11]

Answer:

4.44 kN in the opposite direction of acceleration.

Explanation:

Given that, the initial speed of the car is, u=20m/s

And the mass of the car is, m=1000 kg

The total distance covered by the car before stop, s=45m

And the final speed of the car is, u=0m/s

Now initial kinetic energy is,

KE_{i}=\frac{1}{2}mu^{2}

Substitute the value of u and m in the above equation, we get

KE_{i}=\frac{1}{2}(1000kg)\times (20)^{2}\\KE_{i}=20000J

Now final kinetic energy is,

KE_{f}=\frac{1}{2}mv^{2}

Substitute the value of v and m in the above equation, we get

KE_{f}=\frac{1}{2}(1000kg)\times (0)^{2}\\KE_{i}=0J

Now applying work energy theorem.

Work done= change in kinetic energy

Therefore,

F.S=KE_{f}-KE_{i}\\F\times 45=(0-200000)J\\F=\frac{-200000J}{45}\\ F=-4444.44N\\F=-4.44kN

Here, the force is negative because the force and acceleration in the opposite direction.

6 0
3 years ago
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