Answer:
The tension in the left side string = 17.21 N
The tension in the right side string = F = 27.3 N
Explanation:
Given that
F= 27.3 N
M= 1.43 kg ,r= 0.0792 m
Moment of inertia of disk ,I = 0.5 m r²
I = 0.5 x 1.43 x 0.0792² = 0.0044 kg.m²
m= 0.7 kg
Lets take linear acceleration of system is a m/s²
Lets take tension in left side string = T
From Newtons law
T- mg = ma
T- 0.7 x 10 = 0.7 a ----------1
(F - T) r = I α
α = Angular acceleration of disk
a = α r
(F - T) r = I α
(F - T) r² = I a
( 27.3 - T) x 0.0792² = 0.0044 a --------2
Form equation 1 and 2
a= 1.42 T - 10 m/s²
a = 1.42 ( 27.3 - T) m/s²
1.42 T - 10 = 38.9 - 1.42 T
T=17.21 N
The tension in the right side string = F = 27.3 N
Answer:
yeah meeeeee will add you
Answer: Wavespeed (V) = Frequency F x wavelength λ (V = F λ)
Explanation:
The wavespeed is the distance covered by a wave in one second. It is measured in metre per second, and represented by the symbol V. It is directly proportional to the wavelength and frequency
i.e Velocity (V) = Frequency F x wavelength λ
V = F λ
For instance:
Assume wavelength (λ)= 20 m
Frequency = 10 Hz.
To get the wavespeed, use the formula
V = F λ
V = 20 metres x 10 hertz
V = 200 metres per second
Thus, the wave travels at a speed of 200 metres per second
Answer:
b) field is zero, c) the magnetic field does not change in intensity or direction
e) M = -H = Bo /μ₀
, g) M = 0
Explanation:
Part b
superconductors are formed by so-called Coper pairs that are electrons linked through a distortion in the network, this creates that they must be treated as an entity so we have an even number of charge carriers and the material must behave with diamagnetic , Meissner effect, consequently the magnetic field inside its superconductor is zero
the correct answer is Zero
Part c
outside the superconducting cylinder the magnetic field does not change in intensity or direction
Part E
Magnetization is defined by the equation
B = μ₀ (H + M)
with field B it is zero inside the superconductors
M = -H = Bo /μ₀
where Bo is the magnetic induction in the normal state
Part g
As outside the cylinder there is no material zero magnetization
M = 0
Answer:
Uncertainty ΔV = 22.601 x 10^-10
ΔV = 2.2601nv or 2.2601 x 10^9V
Explanation:
from V = kQ/r
Uncertainty in V is given by δV = V square root [ (δQ/Q)^2 + (δr/r)^2]
ΔV = V square root [ (ΔQ/Q)^2 + (Δr/r)^2] .....................(2)
Given that ; Q = 3.2042e−19 C, r = 0.08 m, ΔQ = 1.6021e−21 C, Δr = 0.005 m
Plugging the values given into equation (2)
from ΔV =(kQ/r) square root [ (ΔQ/Q)^2 + (Δr/r)^2]
ΔV = 9 x 10^9 x 3.2042e−19 / 0.08 square root [ (1.6021e−21/ 3.2042e−19)^2 + ( 0.005/0.08)^2]
ΔV = 360.47 x 0.06269 x 10^-10
Uncertainty ΔV = 22.601 x 10^-10
ΔV = 2.2601nv or 2.2601 x 10^-9V
