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Umnica [9.8K]
1 year ago
14

For the circuit shown in the figure(figure 1) find the current through each resistor. Express your answers using two significant

figures. Enter your answers numerically separated by commas.
Physics
1 answer:
Angelina_Jolie [31]1 year ago
8 0

The current flowing in each resistor of the circuit is 4 A.

<h3>Equivalent resistance of the series resistors</h3>

The equivalent resistance of the series circuit is calculated as follows;

6 Ω and 4 Ω are in series = 10 Ω

5 Ω and 10Ω are in series = 15 Ω

<h3>Effective resistance of the circuit</h3>

\frac{1}{R} = \frac{1}{R_1} + \frac{1}{R_2} \\\\R = \frac{R_1R_2}{R_1 + R_2} \\\\R = \frac{10 \times 15}{10 + 15} \\\\R = 6 \ ohms

<h3>Current flowing in the circuit</h3>

V = IR

I = V/R

I = 24/6

I = 4 A

Learn more about resistors in parallel here: brainly.com/question/15121871

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A copper sphere was moving at 40 m/s when it hit another object. This caused all of the KE to be converted into thermal energy f
USPshnik [31]

Answer:

Temperature increase = 2.1 [C]

Explanation:

We need to identify the initial data of the problem.

v = velocity of the copper sphere = 40 [m/s]

Cp = heat capacity = 387 [J/kg*C]

The most important data given is the fact that when the shock occurs kinetic energy is transformed into thermal energy, therefore it will have to be:

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8 0
3 years ago
One thousand grams of seawater would consist of how many grams of dissolved substances? 65 635 35 965
Naya [18.7K]
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7 0
2 years ago
Read 2 more answers
A beam of light in air is incident at an angle of 30º to the surface of a rectangular block of clear plastic (n = 1.46). The lig
Aneli [31]

Answer:

θ = 30°

Explanation:

Firts, the angle when the beam of light passes through the block cam be calculated using Snell Law:

n_{1}sin(\theta_{1}) = n_{2}sin(\theeta_{2})

<u>Where</u>:

n₁: is the index of refraction of the incident medium (air) = 1

θ₁: is the incident angle = 30°

n₂: is the medium 2 (plastic) = 1.46

θ₂: is the transmission angle

Hence, θ₂ is:

sin(\theta_{2}) = \frac{n_{1}*sin(\theta_{1})}{n_{2}} = \frac{1*sin(30)}{1.46} = 0.34 \rightarrow \theta_{2} = 20.03 ^{\circ}

Now, when the beam of light re-emerges from the opposite side, we have:

n₁: is the index of refraction of the incident medium (plastic) = 1.46  

θ₁: is the incident angle = 20.03°                

n₂: is the medium 2 (air) = 1

θ₂: is the transmission angle

Hence, the angle to the normal to that surface (θ₂) is:

sin(\theta_{2}) = \frac{n_{1}*sin(\theta_{1})}{n_{2}} = \frac{1.46*sin(20.03)}{1} = 0.50 \rightarrow \theta_{2} = 30 ^{\circ}  

 

Therefore, we have that the beam of light will come out at the same angle of when it went in, since, it goes from air and enters to a plastic medium and then enters again in this medium to go out to air again. This was proved using the Snell Law.    

I hope it helps you!                

5 0
2 years ago
When a runner increases her speed from 75 m/s to 115 m/s in 25 s,her acceleration is _____
Angelina_Jolie [31]
The acceleration would actually be 1.6 m/s^2. Acceleration= final velocity-initial velocity/time taken. When you do that formula it comes out to equal that.
8 0
3 years ago
Please help ASAP A uniform disk of mass M and radius R is pivoted such that it can rotate freely about a horizontal axis through
kompoz [17]

Answer: F = mg(1 + 4m / (½M + m))

Explanation:

"At this point seems" unclear. If the particle is at the top of the disc and angular velocity is negligible, then the force would equal the weight of the particle. F = mg

The more interesting question would be what force is needed to keep the particle attached when significant angular rotation has been achieved. The maximum point would be diametrically opposed to the starting point.

I will analyze it there

The potential energy will convert to kinetic energy

   mgh = ½Iω²

mg(2R) = ½(½MR² + mR²)ω²

 4mgR = R²(½M + m)ω²

       ω² = 4mg / (R(½M + m))

With m at the lowest position, the force of attachment must support the weight of m and provide for the needed centripetal acceleration

F = m(g + ω²R)

F = m(g + 4mg / (R(½M + m))R)

F = mg(1 + 4m / (½M + m))

7 0
2 years ago
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