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Rasek [7]
1 year ago
8

In each turn of a game you toss two coins. if 2 heads come up, you win 2 points and if 1 head comes up you win 1 point. if no he

ads come up, you lose 3 points. what is the expected value of the number of points for each turn?
Mathematics
1 answer:
Blizzard [7]1 year ago
3 0

The expected value of the number of points for each turn is 0.25

<h3>What is expected value?</h3>

Expected value describes the long term average level of a random variable based on its probabilty distribution.

Now, Probability that 2 heads come up is

P(2 is H) = 1/4

Probability that 1 heads come up is

P(1 is H) = 2/4

⇒P(1 is H) = 1/2

Probability that no head will come up

P(no H's) = 1/4

Hence, the expected value for winning of 2points, 1point and  lose of3 points is given as-

Expected value = 2 * P(2 is H) + 1 * P(1 is H)  - 3 * P(no H's)

⇒Expected value = 2 * 1/4 + 1 * 1/2 - 3 * 1/4

= 0.5 + 0.5 - 0.75

⇒Expected value = 0.25

More about Expected value :

brainly.com/question/22715250

#SPJ1

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Answer:

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Step-by-step explanation:

To find the area of the composite figure we simply split it into two regular shapes, a half circle and a square, we then find the area of the two shapes individually and add them together.

Area of square = s² where s = side length

It appears the given side length is 12 so s = 12

Which means area = 12² = 144ft²

For semi circle

Area = 1/2(πr² ), where r is the radius

The side length of the square is shared with the diameter of the semi circle meaning that the diameter of the semi circle is 12

To convert to radius from diameter we simply divide by 2 so r = 12/2 = 6

We have area = 1/2(πr² ) and r = 6

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Area = 1/2(36π)

==> take one half of 36

Area = 18π

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Area = about 56.5

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Total area = 56.5 + 144 = 200.5ft²

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