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Cerrena [4.2K]
1 year ago
9

(x+6)(x-3) solve by multiplying out and combining like terms

Mathematics
1 answer:
pogonyaev1 year ago
8 0

Answer:

x^2 + 3x - 18

Step-by-step explanation:

In order to solve this problem, I recommend using the FOIL method.

F = Front

O = Outer

I = Inner

L = Last

Start by multiplying the fronts which is x with x, which will give you x^2 (X to the second power).

Then, multiply x and -3, which gives you -3x. (Outer)

Third, multiply 6 and x, which gives you 6x. (Inner)

Finally, multiply 6 and -3, which gives you -18. (Last)

Now, there are like terms in the products that we just did which is 6x and -3x combine them together and you will get 3x.

So your results should be

x^2 + 3x - 18

Hope this helps!

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In simplest radical form, what are the solutions to the quadratic equation 6 = x2 - 10x?
WARRIOR [948]

Answer:

x = 5 - \sqrt{31}, 5 + \sqrt{31}

Step-by-step explanation:

6 = x^2 - 10x

0 = x^2 - 10x - 6

Let's use the quadratic formula. ( x = \frac{-b +- \sqrt{b^2 - 4ac}}{2a})

x = \frac{10 +- \sqrt{-10^2 - 4(-6)}}{2}

x = \frac{10 +- 2\sqrt{31} }{2}

  = 5 +- \sqrt{31}

x = 5 - \sqrt{31}, 5 + \sqrt{31}

5 0
3 years ago
The product of 5 and twice a number
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Product means multiply so:

5(2n)
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2 years ago
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What number has factors of 2 and 3 and 12 and 18 as multiples?
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6 is the answer
 
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if you have 200 ¨toys¨ and your 2 brother stills 40 each and your mom throws away 90 how many ¨toys¨ do you have left
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A partir del 1.° de diciembre, un camión de helados visita la calle de Sara cada 3 días y la calle de Ema cada 5 días. ¿Cuáles s
777dan777 [17]

Answer:

Los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.

Step-by-step explanation:

Los múltiplos de un número son todos los posibles resultados de multiplicar ese número por todos y cada uno de los números naturales.

Es decir, los múltiplos de un número natural son los números naturales que resultan de multiplicar ese número por otros números naturales.

El conjunto de los múltiplos de un número determinado (salvo el cero) es infinito, pues existen infinitos naturales para multiplicar.

Para determinar cuáles son los primeros 2 días que el camión visita ambas calles el mismo día, debes encontrar los múltiplos de 3 y 5:

múltiplos de 3: 3; 6; 9; 12; 15; 18; 21; 24; 27; 30

múltiplos de 5: 5; 10; 15; 20; 25; 30; 35; 40; 45; 50

Podes observar que los 2 primeros números comunes o que coinciden entre los múltiplos de 3 y 5 son 15 y 30. Esto quiere decir que <u><em>los primeros 2 días que el camión visita ambas calles el mismo día es el 15 y 30 de diciembre.</em></u>

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2 years ago
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