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nalin [4]
1 year ago
12

Automobile license plates for a state consist of four letters followed by a dash and two single digits. How many different licen

se plate combinations are possible if exactly one letter is repeated exactly once, but digits cannot be repeated
Mathematics
1 answer:
Sauron [17]1 year ago
4 0

The number of different license plate combinations that are possible if exactly one letter is repeated exactly once, but digits cannot be repeated is 8,424,000.

<h3>What is combination?</h3>

A combination is just a mathematical technique for determining the number of potential arrangements in a set of objects where the order of a selection is irrelevant.

You can choose the components in any order in combinations. Permutations and combinations are often mistaken.

Now according to the question,

Possible letter combinations

Choose any letter and make it a repeat letter = 26 ways

But, there are ⁴C₂ = 6 spots available for the identical letters.

And there are (25)×(24) other methods for selecting the other two letters.

The total amount of "words" equals ⁴C₂ × 26 × 25 × 24 = 93600.

Furthermore, because the numerals cannot be repeated = 10 × 9 = 90

So, the total number of choices = 93600 × 90 = 8,424,000

Therefore, the total combinations in which the letters can be chosen for the license plates is  8,424,000.

To know more about the combination, here

brainly.com/question/11732255

#SPJ4

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793

Step-by-step explanation:

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A clinical psychologist wants to test whether experiencing childhood trauma affects one's self-efficacy in adulthood. He randoml
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Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 152.5

For the alternative hypothesis,

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This is a two tailed test.

Since no population standard deviation is given, the distribution is a student's t.

Since n = 231

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t = (x - µ)/(s/√n)

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s = samples standard deviation = 27.4

t = (148.9 - 152.5)/(27.4/√231) = - 2

We would determine the p value using the t test calculator. It becomes

p = 0.047

Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals

6 0
3 years ago
How do i do this<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B50d%20%7B0%7D%5E%7B10%7D%20%20" id="TexFormula1" title=" \sqr
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\sqrt{50d^{10}} \\\sqrt{50} =5\sqrt{2}\\5\sqrt{2} *\sqrt{d^{10}}  \\5\sqrt{2}*d^{10/2} \\5\sqrt{2} d^{5}


That's about as much as you can simplify this problem.

I hope this helps! :)

7 0
3 years ago
50 PTS Please help me answer this asap!
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Answer:

1. 2x + 1 ≤ 3

2. 1 + 3x ≥ -5

3. 5x - 7 ≥ 17

4. 5 - 3x ≥ 11

Step-by-step explanation:

Ok

5x - 7 ≥ 17

subtract 7 and u get 5x ≥ 10

divide that and you get ≥ 2

so 3 goes with that one

1 + 3x ≥ -5

subtract 1 and you get 3x ≥ -6

divide that and youll get x ≥ -2

so 2 goes with this one

2x + 1 ≤ 3

subtract 1 and u get 2x ≤ 2

divide them and you get x ≤ 1

so 1 goes with this one

5 - 3x ≥ 11

subtract 5 and u get -3x  ≥ 6

divide it and u get x ≥ -2

so 4 goes with this one

Hoped this helps :)

also btw Brainly steals half the points you give out so instead of 15 ur giving me 25.

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Change 1.234 to a percent
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Answer:

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Therefore;

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formula    Cost or initial Price   x    (  % / 100 )

and show % as a  whole number ie ) 1.234 / 100 = 0.01234

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When we divide by 100 the 1 moves two spaces to the right.

when we have to find initial price from given sale price

we deduct given percentage from 100% and use that to multiply with instead omitting the 1 if its depreciating or adding the 1 if its original price ticket.

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