Answer:
Answer D: 8.7 cm
Step-by-step explanation:
First compare the actual diameters of both cables to find out which one is larger. If we write both diameters in fraction form (as they are given), we need to have them expressed with the same denominator for a straight forward comparison:
Bundle A: 
Bundle B: 
So we multiply this last fraction by 2 in numerator and denominator to obtain the same denominator as for Bundle A without actually changing its numerical value: 
So now we compare Bundle A with bundle B, and see that bundle B has the larger diameter: 22/8 inches
The hole has to be 25% larger than this larger diameter, so we estimate 25% of 22/8 in is:
inches
Therefore, the hole must be of diameter 22/8 in plus 0.6875 in = 3.4375 in
Now we convert this value into centimeters by multiplying it by 2.54 (since one inch is 2.54 cm):
3.4375 * 2.54 = 8.73125 cm
which rounded to the nearest tenth as requested in the problem is: 8.7 cm
Answer:
Null hypothesis: 
Alternative hypothesis: 
Step-by-step explanation:
1) Previous concepts
A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".
The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".
The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".
2) Solution to the problem
On this case we want to test is 
since we want to check if the new model has improved the warranty rate, we can express it like this:
since are equivalent expressions.
And the alternative hypothesis should be the complement:
Null hypothesis: or 
So the correct system of hypothesis for this case would be:
Null hypothesis:
Alternative hypothesis:
The alternative way should be:
Null hypothesis: 
Alternative hypothesis:
Selecting 5 students to participate in a math contest would require combinations.
<u>SOLUTION:
</u>
given that, Selecting 5 students to participate in a math contest would require the calculating of a permutation or combination?
So, we need to differentiate between permutations and combinations.
Permutations - In mathematics, permutation is the act of arranging the members of a set into a sequence or order
Combinations - In mathematics, a combination is a selection of items from a collection, such that the order of selection does not matter.
So, now, for our math test, we just require students but not in an order nor with arrangements.
Hence, selecting 5 students to participate in a math contest would require combinations.
That's <u>always</u> true if <em>either</em> the exponent <em>or </em>the base is less than ' 1 '.
(But not always of they both are.)
