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Elza [17]
2 years ago
13

The conditional relative frequency table was generated using data that compares the number of voters in the last election and wh

ether or not they worked on election day. Fifty people who voted and 85 people who did not vote were chosen at random and surveyed.
A 4-column table with 3 rows. The first column has no label with entries did work, did not work, total. The second column is labeled did vote with entries 0.64, 0.36, 1.0. The third column is labeled did not vote with entries 0.4, 0.6, 1.0. The fourth column is labeled total with entries 0.49, 0.51, 1.0.

How many people in the survey worked on election day?
Mathematics
1 answer:
lidiya [134]2 years ago
6 0

Using proportions, it is found that 66 people in the survey worked on election day.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

For this problem, the amounts of people who worked are:

  • 64% of 50(voted).
  • 40% of 85(did not vote).

Hence the total amount is given by:

0.64 x 50 + 0.4 x 85 = 66.

66 people in the survey worked on election day.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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Step-by-step explanation:

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Line d has a slope of 3/2. Line e has a slope of -2/3. Are line d and line e parallel or
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3 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

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3 years ago
How many different 3-digit PIN codes are there that only include the digits 7, 4, 3 and 2?
KengaRu [80]

Answer:

64

Step-by-step explanation:

We can use the product rule of counting to answer this:

There are 4 possibilities for the 1st digit
There are 4 possibilities for the 2nd digit
There are 4 possibilities for the 3rd digit
So we use the product rule of counting to give us:

4×4×4=64

6 0
2 years ago
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