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Elza [17]
2 years ago
13

The conditional relative frequency table was generated using data that compares the number of voters in the last election and wh

ether or not they worked on election day. Fifty people who voted and 85 people who did not vote were chosen at random and surveyed.
A 4-column table with 3 rows. The first column has no label with entries did work, did not work, total. The second column is labeled did vote with entries 0.64, 0.36, 1.0. The third column is labeled did not vote with entries 0.4, 0.6, 1.0. The fourth column is labeled total with entries 0.49, 0.51, 1.0.

How many people in the survey worked on election day?
Mathematics
1 answer:
lidiya [134]2 years ago
6 0

Using proportions, it is found that 66 people in the survey worked on election day.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

For this problem, the amounts of people who worked are:

  • 64% of 50(voted).
  • 40% of 85(did not vote).

Hence the total amount is given by:

0.64 x 50 + 0.4 x 85 = 66.

66 people in the survey worked on election day.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

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3
katovenus [111]

Question is Incomplete, Complete question is given below.

Mr. Jablonski's class is making fudge for a bake sale. Mr. Jablonski

has a recipe that makes 3/4 pound of fudge. There are 21 students in

the class. Each student uses the recipe to make one batch of fudge.

How many pounds of fudge do the students make?

Answer:

student made \frac{63}{4} \ lbs \ OR \ 15 \frac{3}{4}\ lbs \ OR \ 15.75\ lbs of fudge.

Step-by-step explanation:

Given:

Mr. Jablonski  recipe makes 3/4 pound of fudge.

Number of student in class = 21 students.

Each student uses the recipe to make one batch of fudge.

Hence to calculate Total amount of fudge student made we will multiply the amount of fudge used in recipe with Number of students.

Total amount of fudge student made = amount of fudge used in recipe × Number of students.

Total amount of fudge student made = \frac{3}{4}\times21 = \frac{63}{4} \ lbs =15 \frac{3}{4}\ lbs = 15.75\ lbs

Hence the student made \frac{63}{4} \ lbs \ OR \ 15 \frac{3}{4}\ lbs \ OR \ 15.75\ lbs of fudge.

8 0
3 years ago
Draw a polygon with 4 right angles and 4 sides with the same length
alisha [4.7K]

Answer:

that would be a square, a square has 4 equivalent sides and angles

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma
Monica [59]
y=2(x+3) and y=(3x)+5 best represent this situation
4 0
4 years ago
Read 2 more answers
Evaluate the limit using the appropriate Limit Law(s). (If an answer does not exist, enter DNE.) lim x→8 1 + 3 x 5 − 6x2 + x3
Sergio [31]

Answer:

[tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)=1-384 +512+3\sqrt{8} -18(8)^{5/2} +3 (8)^{7/2} =1223.601

And the limit on this case exists.

Step-by-step explanation:

We want to find the following limit:

lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)

First we can distribute the polynomials like this:

lim_{x \to 8} (1-6x^2 +x^3+3\sqrt{x} -18 x^{5/2} +3x^{7/2})

And Now we can use the distributive property for the limit and we got:

lim_{x \to 8} 1 - 6 lim_{x \to 8} x^2 + lim_{x \to 8} x^3 +3 lim_{x \to 8} \sqrt{x} -18 lim_{x \to 8} x^{5/2} + 3 lim_{x \to 8} x^{7/2}

And now we can evaluate the limit and we got:

[tex] lim_{x \to 8} (1+3\sqrt{x})(1-6x^2 +x^3)=1-384 +512+3\sqrt{8} -18(8)^{5/2} +3 (8)^{7/2} =1223.601

And the limit on this case exists.

5 0
3 years ago
(6 1/3-1/6x 36=?<br> 221/6<br> 216<br> 222<br> 242
scoundrel [369]

Answer:

<em>-(6 1/3-1/6x 36=216</em>

Hope I helped

8 0
3 years ago
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