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2 years ago

Which requires more work: lifting a 50-kg sack a vertical distance of 2 m or lifting a 25-kg sack a vertical distance of 4 m?

1 answer:

8 0

Lifting a 50-kg sack through a vertical distance of 2 m requires same amount of work as lifting a 25-kg sack through a vertical distance of 4 m

<h3>How to determine which will require more work</h3>

To determine which will require more work, we shall determine the work done in lifting each sack. Details below:

i. Work done in lifting 50 Kg

Mass (m) = 50 Kg
Height (h) = 2 m
Acceleration due to gravity (g) = 9.8 m/s²
Workdone (Wd) =?

Wd = mgh

Wd = 50 × 9.8 × 2

Workdone = 980 J

ii. Work done in lifting 25 Kg

Mass (m) = 25 Kg
Height (h) = 4 m
Acceleration due to gravity (g) = 9.8 m/s²
Workdone (Wd) =?

Wd = mgh

Wd = 25 × 9.8 × 4

Workdone = 980 J

SUMMARY

Work done in lifting 50 Kg is 980 J
Work done in lifting 25 Kg is 980 J

Thus, equal amount of work done is needed.

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4 years ago

Two cars have identical horns, each emitting a frequency of fs = 406 Hz. One of the cars is moving with a speed of 10.5 m/s towa

Archy [21]

Answer:

$f_{B}=12.8 Hz$

Explanation:

Let's start finding the frequency heard by the bystander due to the moving car. We need to use Doppler effect here:

$f_{obs}=f_{s}\left(\frac{v}{v-v_{car}}\right)$

v is the speed of sound (v = 343 m/s)

So, we have:

$f_{obs}=406\left(\frac{343}{343-10.5}\right)=418.8 Hz$

Now, the beat frequency heard by the bystander is the combine of the frequencies, it means the difference between them. Therefore the equation is given by:

$f_{B}=f_{obs}-f_{s}=418.8-406=12.8 Hz$

I hope it helps you!

4 0

3 years ago

The sun has sufficient hydrogen to continue fusing into helium for how much longer?

vichka [17]

Answer:

4500 million years

Explanation:

The Sun shines thanks to the thermonuclear conversion of hydrogen to helium inside. It is currently 4,500 million years old and has reservations for a similar period of time. When this fuel is exhausted in the central region, the heart of the Sun, constituted of helium and in an inert state, will contract and put more external fuel reserves within reach of the star, with which this mass of helium will grow over time . When that happens, the Sun will evolve into a giant star that will reach the orbit of Mars and, therefore, destroy the planet Earth.

As the helium heart mass increases so do the central density and temperature. When it reaches 100 million degrees, helium fuses thermonuclearly with itself and becomes a mixture of carbon and oxygen.

When the helium runs out in the center, the previous operation is reproduced approximately. The carbon / oxygen heart contracts and the helium and hydrogen of the surrounding layers are placed within the reach of thermonuclear combustion. The difference is that this double combustion is unstable and the density is so high that electrons can, alone, stabilize the heart of carbon and oxygen. The end result is that the outer layers, which originate a planetary nebula, are expelled, and the old thermonuclear reactor becomes visible, which becomes a white dwarf that slowly cools like the embers of a fire over billions of millions. of years.

8 0

3 years ago

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Mandarinka [93]

Answer:

The number of coils of the wire and the strength of the power source.

Explanation:

It is a direct relationship meaning when one increases so does the other. A stronger power source will induce a stronger magnetic force. The more coils the stronger the magnet.

7 0

4 years ago

Find the energy released in the fission reaction¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n) The atomic masses of the fission product

ikadub [295]

Fission reaction is given

¹₀n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3(¹₀n)

The atomic masses of the fission products are 97.912735 u for ⁹⁸₄₀Zr and 134.916450 u for ¹³⁵₅₂Te. Hence, the energy released in fission reaction is 191.715 MeV.

How to find the energy released in the given fission reaction?

We know, that the atomic mass of the elements are as follows:

⁹⁸₄₀Zr - 97.9120u

¹³⁵₅₂Te - 134.9087u

²³⁵₉₂U - 235.0483923u
n = 1.008665u

In order to find the mass difference, we will calculate the initial mass and the mass of products.

The equation for the reaction:

n + ²³⁵₉₂U → ⁹⁸₄₀Zr + ¹³⁵₅₂Te +3n

Mass of initial reagents is 1.008665u + 235.0483923u = 233.052588u

Product of the reagents is 97.9120u + 134.9087u + 3(1.008665u) = 235.846773u

Now, using the formula of

$E=(\triangledown m)c^2$

$E=(0.205815u)\frac{931.494MeV/c^2}{u} c^2=191.715MeV$

Hence, the energy released in fission reaction is 191.715 MeV.

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2 years ago