Answer:
The transverse wave will travel with a speed of 25.5 m/s along the cable.
Explanation:
let T = 2.96×10^4 N be the tension in in the steel cable, ρ = 7860 kg/m^3 is the density of the steel and A = 4.49×10^-3 m^2 be the cross-sectional area of the cable.
then, if V is the volume of the cable:
ρ = m/V
m = ρ×V
but V = A×L , where L is the length of the cable.
m = ρ×(A×L)
m/L = ρ×A
then the speed of the wave in the cable is given by:
v = √(T×L/m)
= √(T/A×ρ)
= √[2.96×10^4/(4.49×10^-3×7860)]
= 25.5 m/s
Therefore, the transverse wave will travel with a speed of 25.5 m/s along the cable.
The correct answer is C) the focus
To cook food, a microwave oven converts electrical energy into electromagnetic energy. (A) Specifically, it pours high-power RADIO waves into the box.
Water molecules and fat molecules resonate (jiggle) with the radio waves, and the heat is generated IN THE FOOD.
I work with microwave radios.
-- To communicate high-speed data over a distance of 5 to 10 miles, we use a radio transmitter with a power output of 0.07 watt .
-- To communicate high-speed data over distances up to 80 miles, we use a radio transmitter with a power output of 1 to 2 watts.
-- To heat up a chunk of leftover meatloaf, a microwave oven pumps radio waves into the box with a power output of 1200 to 1500 watts ! !
