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ludmilkaskok [199]
1 year ago
6

What is the molar concentration of a 2 liter solution containing 200 grams of glucose?

Chemistry
1 answer:
NARA [144]1 year ago
8 0

The molar concentration is 1.11M.

<h3>What is molar concentration?</h3>

The phrase "molar concentration" (also known as "molarity," "amount concentration," or "substance concentration") refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. The most frequent measure of molarity in chemistry is the number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units. A solution with a concentration of 1 mol/L is referred to as 1 molar, or 1 M.

<h3>Given : </h3>

Volume of the solution = 2L

Mass of glucose given = 200g

Concentration of glucose= ?

<h3>Formula use: </h3>

Molarity = no. of moles of solute / volume of the solution (L)

Moles of solute = given mass of solute / molar mass of the solute

<h3>Solution: </h3>

No. of moles of solute( glucose ) = 200 / 180 = 1.11 moles'

Molarity = 1.11 / 2 = 0.5555 mol L ^(-1)

Therefore, the molar concentration of glucose in the solution = 0.555 mol L ^(-1)

To learn more about molar concentration :

brainly.com/question/15532279

#SPJ4

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Answer:

See explanation.

Explanation:

Hello!

In this case, since we know the heat of reaction per gram of reactant and we should know the total energy of reaction, but it is not there, we are going to assume it is 1200 J as usual in these problems, so you can change it to whatever your given heat is.

In such a way, we set up the math as shown below:

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Answer : The rate of change of the total pressure of the vessel is, 10.5 torr/min.

Explanation : Given,

\frac{d[NO]}{dt} =21 torr/min

The balanced chemical reaction is,

2NO(g)+Cl_2(g)\rightarrow 2NOCl(g)

The rate of disappearance of NO = -\frac{1}{2}\frac{d[NO]}{dt}

The rate of disappearance of Cl_2 = -\frac{d[Cl_2]}{dt}

The rate of formation of NOCl = \frac{1}{2}\frac{d[NOCl]}{dt}

As we know that,

\frac{d[NO]}{dt} =21 torr/min

So,

-\frac{d[Cl_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}

\frac{d[Cl_2]}{dt}=\frac{1}{2}\times 21torr/min=10.5torr/min

And,

\frac{1}{2}\frac{d[NOCl]}{dt}=\frac{1}{2}\frac{d[NO]}

\frac{d[NOCl]}{dt}=\frac{d[NO]}=21torr/min

Now we have to calculate the rate change.

Rate change = Reactant rate - Product rate

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Therefore, the rate of change of the total pressure of the vessel is, 10.5 torr/min.

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